The amount of I (aq) in a solution can be determined by titration with a solution containing a known concentration of S, 0?-(aq) (thiosulfate ion). The determination is based on the net ionic equation 2S,0 (aq) + 15 (aq) → S,0 (aq) + 31-(aq) Given that it requires 33.5 mL of 0.260 M Na, S,0, (aq) to titrate a 20.0 mL sample of I, (aq), calculate the molarity of I, (aq) in the solution. M Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry Publisher: University Science Books 9 stv O hulu MacBook Pro GSearch or type URL 24 & ). 5 6. 8. 101 delete RI Y. U 17 D G V N4 OSISON command option

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The amount of I\(_3^-\) (aq) in a solution can be determined by titration with a solution containing a known concentration of S\(_2\)O\(_3^{2-}\) (aq) (thiosulfate ion). The determination is based on the net ionic equation:

\[ 
2\text{S}_2\text{O}_3^{2-}(\text{aq}) + \text{I}_3^-(\text{aq}) \rightarrow \text{S}_4\text{O}_6^{2-}(\text{aq}) + 3\text{I}^-(\text{aq})
\]

Given that it requires 33.5 mL of 0.260 M Na\(_2\)S\(_2\)O\(_3\) (aq) to titrate a 20.0 mL sample of I\(_3^-\) (aq), calculate the molarity of I\(_3^-\) (aq) in the solution.

\[
[\text{I}_3^-] = \underline{\hspace{4cm}} \, \text{M}
\]

**Explanation:**

To calculate the molarity of I\(_3^-\) in the solution,

1. Note that the balanced reaction shows a 2:1 mole ratio between S\(_2\)O\(_3^{2-}\) and I\(_3^-\).
2. Calculate the moles of S\(_2\)O\(_3^{2-}\) using its volume and molarity.
3. Use the stoichiometry of the balanced equation to find the moles of I\(_3^-\).
4. Divide the moles of I\(_3^-\) by the volume of I\(_3^-\) in liters to get its molarity.
Transcribed Image Text:The amount of I\(_3^-\) (aq) in a solution can be determined by titration with a solution containing a known concentration of S\(_2\)O\(_3^{2-}\) (aq) (thiosulfate ion). The determination is based on the net ionic equation: \[ 2\text{S}_2\text{O}_3^{2-}(\text{aq}) + \text{I}_3^-(\text{aq}) \rightarrow \text{S}_4\text{O}_6^{2-}(\text{aq}) + 3\text{I}^-(\text{aq}) \] Given that it requires 33.5 mL of 0.260 M Na\(_2\)S\(_2\)O\(_3\) (aq) to titrate a 20.0 mL sample of I\(_3^-\) (aq), calculate the molarity of I\(_3^-\) (aq) in the solution. \[ [\text{I}_3^-] = \underline{\hspace{4cm}} \, \text{M} \] **Explanation:** To calculate the molarity of I\(_3^-\) in the solution, 1. Note that the balanced reaction shows a 2:1 mole ratio between S\(_2\)O\(_3^{2-}\) and I\(_3^-\). 2. Calculate the moles of S\(_2\)O\(_3^{2-}\) using its volume and molarity. 3. Use the stoichiometry of the balanced equation to find the moles of I\(_3^-\). 4. Divide the moles of I\(_3^-\) by the volume of I\(_3^-\) in liters to get its molarity.
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