The ammeter shown in the figure reads 4.4 A, R1 =7.0 2, R2=5.0 2, and R3 = 2.0 Q RI 10.0 V R2 A R3 3. (a) Calculate the values of I and I (b) What is e?
Q: R1 IR3 IR1 Ir2 = 2.0A %3D R2 R3 V1 = 6.0V V2
A: I2 = 2 AR2 = 4 ohm V1 = 6 v R1 = 2 ohm R3 = 5 ohm
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A: According to ohms law - V=IR Reading of Voltmeter and Ammeter are - Vr=6.50 vIr=2.50 mA1 A = 1000…
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A: We know that we have a circuit is given as a) By the KVL we get that -∆V+10I+RI=0 -5.40+10I+9.40…
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Q: E = +10.0 V E, = -3.0 V E, = 0 V E,=1.5 V (a) (b) (c) (d) E = +7.0 V E, = -4.5 V E =-1.5 V E = -1.5…
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- What are the expected readings of the following in the figure below? (R = 9.50 Q, AV = 6.50 V) A AV 10.0 N 5.00 N + R 4.50 V (a) ideal ammeter (Give your answer in mA.) (b) ideal voltmeter (Give your answer in volts.) V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter ideal voltmeter VIn (Figure 1) the battery has emf 45.0 V and negligible internal resistance. R₁ = 7.00 2. The current through R₁ is 1.50 A and the current through R3 = 4.50 A. Figure ww R₁ www R₂ www- R₂ < 1 of 1 ▼ What is the resistance R₂? Express your answer with the appropriate units. R₂: Submit Part B R3 11 .0 Submit μA Value What is the resistance R3 ? Express your answer with the appropriate units. Request Answer HÅ Value Units Request Answer Units ?general physics
- Problem 5: A current of I- 2.6 A passes through the circuit shown, where R- 65 3R 5R V) 2R 6R 2R 7R 5R 10R Otheexpertta.com Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the · source, V. Part (b) What is the voltage, V in volts? tan( sin() cotanO a acos cosh0t cosO asin() acotan 4 5 6 sinh() cotanhO *1 23 0 tanh0c O Degrees O Radians CLEAR BACKSPACE3 mA Δ 10 ΚΩ The voltage v is equal to: W