The American Heart Association is about to conduct an anti-smoking campaign and wants to know the fraction of Americans over 35 who smoke. Step 2 of 2 :   Suppose a sample of 1089 Americans over 35 is drawn. Of these people, 359 smoke. Using the data, construct the 85% confidence interval for the population proportion of Americans over 35 who smoke. Round your answers to three decimal places.

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: GIVEN DATA,  n=971x=554P^=Xn=554971=0.5705CI=0.99α=1-0.99=0.01we have to find out the confidence…

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: You are interested in finding a 95% confidence interval for the mean number of visits for physical…

A: Given,mean(x¯)=13.6standard deviation (s)=9.1918sample size(n)=10degrees of…

Q: Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one…

A:

Q: A survey of 100 americans found that 68% said they find it hard to buy holiday gifts that convey…

A: It is given that, p hat is 0.68 and the sample size (n) is 100.  The level of confidence is 0.90.

Q: Over the break, you do some reasearch. In a random sample of 250 U.S. adults, 56% said they ate…

A:

Q: survey to determine if the percentage of adults who use social media has changed from 52%, which was…

A: The sample proportion is computed as follows, The critical value for 96% confidence level, i.e.,…

Q: You take a random sample of size 25 students and find the 5 who understand this lecture. With 99%…

A:

Q: se the sample data and confidence level given below to complete parts​ (a) through​ (d). A research…

A: Consider that p is the true population proportion of the respondents who felt vulnerable to identify…

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 520…

A:

Q: T.J. wants to estimate the percentage of college students who have taken out student loans. He…

A:

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: A survey of 100 men found that 68% said they find it hard to buy holiday gifts that convey their…

A: Solution

Q: Emma wants to estimate the percentage of people who use public transportation in a city. She surveys…

A: Obtain the margin of error. The margin of error is obtained below: The formula for the margin of…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: Enrique teaches five sections of Introductory Psychology. He wants to know whether or not the…

A:

Q: Find the 95%95% confidence interval for the average value of net income given that sales are…

A: From the given information, a regression analysis has been performed to estimate the model. Here,…

Q: A data set is described as consisting of n = 15 scores. Based on the notation being used, the data…

A: We have the following statement .

Q: You want to estimate the percentage of small incorporated businesses that are owned by women. A…

A: The random variable percentage of small incorporated businesses follows binomial distribution. The…

Q: You plan to conduct a survey to estimate the percentage of adults who have had chickenpox. Find the…

A: It is needed to find the number of people who must be surveyed if one wants to be 93% confident that…

Q: Find  z for a  90% confidence level. Round your answer to two decimal places.

A: Given confidence level is 90% Significance level is 10%

Q: Before you took this course, you probably heard many stories about Statistics courses. Oftentimes…

A: Given :

Q: Mr. James McWhinney, president of Daniel-James Financial Services, believes there is a relationship…

A: The formula for the confidence interval is,where,denotes the predicted value of yse denotes the…

Q: Celyn is among the 1500 students of the school.If Celyn's score based on the Standard-Binet test is…

A: Given: Number of students = 1500 Score on standard Binest test is 105

Q: In a given set of scores, the following data were obtained, the highest score is 83, the median…

A: A P percentile is the value in a dataset below which P percent of the data lies. A median is the…

Q: Construct the 99% confidence interval for the difference when 3-47688, -318.32, -42.11, -2680, -19,…

A: Test hypothesisNull Hypothesis H0: μ1=μ2Alternative Hypothesis Ha: μ1≠μ2For group 1 Sample size…

Q: Suppose you plan to conduct among 2,500 Grade 12 students enrolled in the stem Track. How many…

A:

Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…

A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…

Q: In using a double exponential smoothing method, we calculated S3 to be 2,255.6 and G3 to be 12.2. D4…

A: From the given information, S3=2255.6 G3:12.2 alpha and beta values are 0.4, and 0.53, respectively…

Q: Of the 328 patients that completed the survey last year, 211 of them claimed to be returning…

A: The question is asking to identify the type of data that the question 'How long did you wait past…

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: When 370 junior college students were surveyed, 145 said they have a passport.  Construct a 95%…

A: Zcrit = 1.96

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 480…

A: We have given that  Sample size n= 480 Sample proportion p^= 0.23 95% confidence interval

Q: Studies have shown that approximately 5.3% of Americans have French heritage. You want to know how…

A: Introduction: The confidence interval for the population proportion, p at the 100 (1 – α) %…