+ The advertised claim for batteries for cell phones is set at 48 operating hours with proper charging procedures. A study of 5000 batteries is carried out and 15 stop operat- ing prior to 48 hours. Do these experimental results support the claim that less than 0.2 percent of the company's batter- ies will fail during the advertised time period, with charging procedures? Use a hypothesis-testing procedure proper with a = 0.01.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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You can perform this exercise in Minitab? the exercise is already solved!

But I just want to see how to do it in Minitab, please!

 

Note:

the exercise is already solved! as seen in the image I attached, I just want to see it solved in minitab!

(with pictures, or sreenshots) however, but I want to see the procedure :)

+ The advertised claim for batteries for cell phones
is set at 48 operating hours with proper charging procedures.
A study of 5000 batteries is carried out and 15 stop operat-
ing prior to 48 hours. Do these experimental results support
the claim that less than 0.2 percent of the company's batter-
ies will fail during the advertised time period, with proper
charging procedures? Use a hypothesis-testing procedure
with a = 0.01.
Transcribed Image Text:+ The advertised claim for batteries for cell phones is set at 48 operating hours with proper charging procedures. A study of 5000 batteries is carried out and 15 stop operat- ing prior to 48 hours. Do these experimental results support the claim that less than 0.2 percent of the company's batter- ies will fail during the advertised time period, with proper charging procedures? Use a hypothesis-testing procedure with a = 0.01.
We fail to reject Họ, because zo = 1.58 > -2.33
C0.01-
Transcribed Image Text:We fail to reject Họ, because zo = 1.58 > -2.33 C0.01-
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