The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous rv X with the following pdf. - f(x) = ) = {^ [¹ − (x − 3)²] 2≤x≤4 otherwise 0 (a) Sketch the graph of f(x). f(x) f(x) 1.0 0.8 0.6 0.4 0.2 X X 4.5 2.0 2.5 3.0 3.5 4.0 2.5 2.0 3.5 3.0 4.0 4.5 O O f(x) f(x) 1.0 1.0 0.8 0.8 0.6 0.6 Lh 0.4 0.4 0.2 0.2 X X 2.0 2.5 3.0 3.5 4.0 4.5 2.0 2.5 O 3.0 3.5 4.0 4.5 O (b) Find the value of k. (c) What is the probability that the actual tracking weight is greater than the prescribed weight? 1.0 0.8 0.6 0.4 0.2

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P4

### Probability and Statistics: Continuous Random Variables

**Context:** The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous random variable \(X\) with the following probability density function (pdf):

\[ 
f(x) = 
\begin{cases} 
k[1 - (x - 3)^2] & \text{for } 2 \le x \le 4 \\
0 & \text{otherwise} 
\end{cases}
\]

#### (a) Sketch the graph of \( f(x) \).

There are four sketches provided, but only one is correct. The graph representing \( f(x) \) starts at \( x = 2 \), peaks at \( x = 3 \), and descends back to zero at \( x = 4 \). Each axis is labeled "f(x)" for the vertical and "x" for the horizontal, with the range specified between 2 and 4.

Below is a detailed explanation of these sketches:
- The plot has a parabolic shape between \( x = 2 \) and \( x = 4 \).
- The maximum value is achieved at \( x = 3 \), making it the vertex of the parabola.
- The parabolic curve descends symmetrically on both sides of the vertex.

To determine which sketch to choose, look for the one that peaks at \( x = 3 \) and spans from \( x = 2 \) to \( x = 4 \).

#### (b) Find the value of \( k \).

To ensure that \( f(x) \) is a valid probability density function, it must integrate to 1 over the interval from 2 to 4. This requires setting up and solving the integral:

\[
\int_{2}^{4} k[1 - (x - 3)^2] \, dx = 1
\]

After evaluating the integral, find \( k \).

#### (c) What is the probability that the actual tracking weight is greater than the prescribed weight?

Evaluate the probability \( P(X > 3) \) by integrating the pdf from 3 to 4:

\[
P(X > 3) = \int_{3}^{4} f(x) \, dx
\]

#### (d) What is the probability that the actual weight is within 0.5 g
Transcribed Image Text:### Probability and Statistics: Continuous Random Variables **Context:** The actual tracking weight of a stereo cartridge that is set to track at 3 g on a particular changer can be regarded as a continuous random variable \(X\) with the following probability density function (pdf): \[ f(x) = \begin{cases} k[1 - (x - 3)^2] & \text{for } 2 \le x \le 4 \\ 0 & \text{otherwise} \end{cases} \] #### (a) Sketch the graph of \( f(x) \). There are four sketches provided, but only one is correct. The graph representing \( f(x) \) starts at \( x = 2 \), peaks at \( x = 3 \), and descends back to zero at \( x = 4 \). Each axis is labeled "f(x)" for the vertical and "x" for the horizontal, with the range specified between 2 and 4. Below is a detailed explanation of these sketches: - The plot has a parabolic shape between \( x = 2 \) and \( x = 4 \). - The maximum value is achieved at \( x = 3 \), making it the vertex of the parabola. - The parabolic curve descends symmetrically on both sides of the vertex. To determine which sketch to choose, look for the one that peaks at \( x = 3 \) and spans from \( x = 2 \) to \( x = 4 \). #### (b) Find the value of \( k \). To ensure that \( f(x) \) is a valid probability density function, it must integrate to 1 over the interval from 2 to 4. This requires setting up and solving the integral: \[ \int_{2}^{4} k[1 - (x - 3)^2] \, dx = 1 \] After evaluating the integral, find \( k \). #### (c) What is the probability that the actual tracking weight is greater than the prescribed weight? Evaluate the probability \( P(X > 3) \) by integrating the pdf from 3 to 4: \[ P(X > 3) = \int_{3}^{4} f(x) \, dx \] #### (d) What is the probability that the actual weight is within 0.5 g
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