The acid HOCI (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid water according to the equation 2HgO(s) + H₂O(1) + 2Cl₂(g)=2HOCl(aq) + HgO-HgCl₂ (s) What is the equilibrium-constant expression for this reaction?
The acid HOCI (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid water according to the equation 2HgO(s) + H₂O(1) + 2Cl₂(g)=2HOCl(aq) + HgO-HgCl₂ (s) What is the equilibrium-constant expression for this reaction?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### The Equilibrium-Constant Expression for Heterogeneous Equilibria
**Introduction:**
Heterogeneous equilibria involve reactants and products that are not all in the same phase. For example, a solid may decompose, forming two gases. When writing equilibrium-constant expressions for heterogeneous reactions, generally the concentrations of pure solids and liquids are omitted. The composition of a pure solid or liquid does not change over the course of the reaction; only its quantity changes. Since its concentration isn’t changing, the values can usually be excluded.
**General Expression:**
Given the equation:
\[ x \text{CD(s)} \rightleftharpoons c \text{C(g)} + d \text{D(g)} \]
The equilibrium constant expression would be:
\[ K = [\text{C}]^c[\text{D}]^d \]
---
### Example Reaction
**Problem:**
The acid \(\text{HOCl}\) (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid water according to the equation:
\[ 2\text{HgO(s)} + \text{H}_2\text{O(l)} + 2\text{Cl}_2\text{(g)} \rightleftharpoons 2\text{HOCl(aq)} + \text{HgO}\cdot\text{HgCl}_2\text{(s)} \]
**Question:**
What is the equilibrium-constant expression for this reaction?
**Answer Options:**
- \((A)\) \[ K = \frac{[\text{HOCl}]^2[\text{H}_2\text{O}][\text{HgCl}_2]}{[\text{Cl}_2]^2[\text{H}_2\text{O}][\text{HgO}]^2} \]
- \((B)\) \[ K = \frac{[\text{HOCl}]^2}{[\text{Cl}_2]^2[\text{H}_2\text{O}]} \]
- \((C)\) \[ K = \frac{[\text{HOCl}]^2}{[\text{Cl}_2]^2} \]
- \((D)\) \[ K = \frac{[\text{Cl}_2]^2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1205cd08-0e41-4ad8-bd1c-6b97372ee2c1%2F3ab941b2-2483-4cee-bd41-b1e2c5c816ec%2Fmvq0bzq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### The Equilibrium-Constant Expression for Heterogeneous Equilibria
**Introduction:**
Heterogeneous equilibria involve reactants and products that are not all in the same phase. For example, a solid may decompose, forming two gases. When writing equilibrium-constant expressions for heterogeneous reactions, generally the concentrations of pure solids and liquids are omitted. The composition of a pure solid or liquid does not change over the course of the reaction; only its quantity changes. Since its concentration isn’t changing, the values can usually be excluded.
**General Expression:**
Given the equation:
\[ x \text{CD(s)} \rightleftharpoons c \text{C(g)} + d \text{D(g)} \]
The equilibrium constant expression would be:
\[ K = [\text{C}]^c[\text{D}]^d \]
---
### Example Reaction
**Problem:**
The acid \(\text{HOCl}\) (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid water according to the equation:
\[ 2\text{HgO(s)} + \text{H}_2\text{O(l)} + 2\text{Cl}_2\text{(g)} \rightleftharpoons 2\text{HOCl(aq)} + \text{HgO}\cdot\text{HgCl}_2\text{(s)} \]
**Question:**
What is the equilibrium-constant expression for this reaction?
**Answer Options:**
- \((A)\) \[ K = \frac{[\text{HOCl}]^2[\text{H}_2\text{O}][\text{HgCl}_2]}{[\text{Cl}_2]^2[\text{H}_2\text{O}][\text{HgO}]^2} \]
- \((B)\) \[ K = \frac{[\text{HOCl}]^2}{[\text{Cl}_2]^2[\text{H}_2\text{O}]} \]
- \((C)\) \[ K = \frac{[\text{HOCl}]^2}{[\text{Cl}_2]^2} \]
- \((D)\) \[ K = \frac{[\text{Cl}_2]^2
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