The accompanying table lists the numbers of words spoken in a day by each member of 56 different randomly selected couples. Complete parts​ (a) and​ (b) below.   A. Use a 0.05 significance level to test the claim that among​ couples, males speak fewer words in a day than females.       In this​ example, μd is the mean value of the differences d for the population of all pairs of​ data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis​ test?           (Answered) H0​: μd ( =) 0 H1​: μd ( <) 0        (Answered) B. Identify the test statistic. t= -1.58         (Answered) C. Identify the​ P-value. ​P-value= 0.059   D. What is the conclusion based on the hypothesis​ test? Since the​ P-value is (greater than) the significance​ level, (fail to reject) the null hypothesis. There (is not) sufficient evidence to support the claim that males speak fewer words in a day than females.   (Unanswered)E. b. Construct the confidence interval that could be used for the hypothesis test described in part​ (a). What feature of the confidence interval leads to the same conclusion reached in part​ (a)? The confidence interval is___ word(s)< μd<___​word(s). (Unanswered)F. What feature of the confidence interval leads to the same conclusion reached in part​ (a)? Since the confidence interval contains (zero/ only positive numbers/ only negative numbers) (fail to reject/ reject) the null hypothesis.

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*NOTE: This question was previously answered, but due to policy, only the first three parts could be answered. I am putting which parts were answered, and which parts still need answered. Thank you. 

 

The accompanying table lists the numbers of words spoken in a day by each member of 56 different randomly selected couples. Complete parts​ (a) and​ (b) below.
 
A. Use a 0.05 significance level to test the claim that among​ couples, males speak fewer words in a day than females.
      In this​ example, μd is the mean value of the differences d for the population of all pairs of​ data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis​ test?
 
        (Answered)
H0​: μd ( =) 0
H1​: μd ( <) 0
 
     (Answered)
B. Identify the test statistic.
t= -1.58
 
      (Answered)
C. Identify the​ P-value.
​P-value= 0.059
 
D. What is the conclusion based on the hypothesis​ test?
Since the​ P-value is (greater than) the significance​ level, (fail to reject) the null hypothesis. There (is not) sufficient evidence to support the claim that males speak fewer words in a day than females.
 
(Unanswered)E. b. Construct the confidence interval that could be used for the hypothesis test described in part​ (a). What feature of the confidence interval leads to the same conclusion reached in part​ (a)?
  • The confidence interval is___ word(s)< μd<___​word(s).

(Unanswered)F. What feature of the confidence interval leads to the same conclusion reached in part​ (a)?

Since the confidence interval contains (zero/ only positive numbers/ only negative numbers) (fail to reject/ reject) the null hypothesis.

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