The accompanying table lists the numbers of words spoken in a day by each member of 56 different randomly selected couples. Complete parts (a) and (b) below. E Click the icon to view the data on words spoken in a day by the couples. a. Use a 0.05 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, Ha is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test? Ho: Ha = 0 word(s) < 0 word(s) H1: Hd (Type integers or decimals. Do not round.) Identify the test statistic. t = (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is the significance level, the null hypothesis. There sufficient evidence to support the claim that males speak fewer words in a day than females.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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1
Male
Female
2
26726
21648
3
16217
26437
4
6260
7076
5
29577
19998
6
27290
13416
6434
16600
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22743
10258
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19236
17988
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24861
13826
11
22683
18517
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10428
15253
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10390
11629
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11406
18503
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21484
21788
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19825
7938
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1422
17481
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20955
24414
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9707
17969
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21700
15445
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15706
15430
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16454
29731
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22330
8498
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8174
18447
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7222
7234
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27676
10588
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11341
17182
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13626
13995
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13188
19667
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12117
22455
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17489
13401
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12993
33932
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10496
10495
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19262
9075
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16359
11287
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11110
28734
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15615
20555
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13537
17971
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11617
18049
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19584
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10338
17388
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12329
19961
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6990
11553
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18319
16644
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14585
15274
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14148
27474
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15922
38700
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20816
26400
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37001
35322
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17119
23168
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48645
31411
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24459
17292
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11978
5443
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14022
25904
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8223
15715
56
7599
15573
57
21491
26158
Transcribed Image Text:1 Male Female 2 26726 21648 3 16217 26437 4 6260 7076 5 29577 19998 6 27290 13416 6434 16600 8 22743 10258 9 19236 17988 10 24861 13826 11 22683 18517 12 10428 15253 13 10390 11629 14 11406 18503 15 21484 21788 16 19825 7938 17 1422 17481 18 20955 24414 19 9707 17969 20 21700 15445 21 15706 15430 22 16454 29731 23 22330 8498 24 8174 18447 25 7222 7234 26 27676 10588 27 11341 17182 28 13626 13995 29 13188 19667 30 12117 22455 31 17489 13401 32 12993 33932 33 10496 10495 34 19262 9075 35 16359 11287 36 11110 28734 37 15615 20555 38 13537 17971 39 11617 18049 40 19584 20123 41 10338 17388 42 12329 19961 43 6990 11553 44 18319 16644 45 14585 15274 46 14148 27474 47 15922 38700 48 20816 26400 49 37001 35322 50 17119 23168 51 48645 31411 52 24459 17292 53 11978 5443 54 14022 25904 55 8223 15715 56 7599 15573 57 21491 26158
The accompanying table lists the numbers of words spoken in a day by each member of 56 different randomly selected couples. Complete
parts (a) and (b) below.
Click the icon to view the data on words spoken in a day by the couples.
a. Use a 0.05 significance level to test the claim that among couples, males speak fewer words in a day than females.
In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is
defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the
hypothesis test?
Ho: Hd
0 word(s)
H1: Hd < 0 word(s)
(Type integers or decimals. Do not round.)
Identify the test statistic.
t= (Round
two decimal places as needed.)
Identify the P-value.
P-value =
(Round to three decimal places as needed.)
What is the conclusion based on the hypothesis test?
Since the P-value is
V the significance level,
the null hypothesis. There
sufficient evidence to
support the claim that males speak fewer words in a day than females.
b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval
leads to the same conclusion reached in part (a)?
The confidence interval is word(s) < µa <
word(s).
(Round to one decimal place as needed.)
What feature of the confidence interval leads to the same conclusion reached in part (a)?
Since the confidence interval contains
the null hypothesis.
Transcribed Image Text:The accompanying table lists the numbers of words spoken in a day by each member of 56 different randomly selected couples. Complete parts (a) and (b) below. Click the icon to view the data on words spoken in a day by the couples. a. Use a 0.05 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test? Ho: Hd 0 word(s) H1: Hd < 0 word(s) (Type integers or decimals. Do not round.) Identify the test statistic. t= (Round two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is V the significance level, the null hypothesis. There sufficient evidence to support the claim that males speak fewer words in a day than females. b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? The confidence interval is word(s) < µa < word(s). (Round to one decimal place as needed.) What feature of the confidence interval leads to the same conclusion reached in part (a)? Since the confidence interval contains the null hypothesis.
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