The accompanying data table contains chest deceleration measurements (in g, where g is the force of gravity) from samples of small, midsize, and large cars. Shown are the technology results for analysis of variance of this data table. Assume that a researcher plans to use a 0.05 significance level to test the claim that the different size categories have the same mean chest deceleration in the standard crash test. Complete parts (a) and (b) below. a. What characteristic of the data specifically indicates that one-way analysis of variance should be used? O A. There are three samples of measurements. OB. The measurements are categorized according to the one characteristic of size. OC. The population means are approximately normal. O D. Nothing specifically indicates that one-way analysis of variance should be used. b. If the objective is to test the claim that the three size categories have the same mean chest deceleration, why is the method referred to as analysis of variance? OA. The method is based on showing that the population variances are different. OB. The method is based on estimates of multiple varying population variances. O C. The method is based on showing that the population variances are similar. O D. The method is based on estimates of a common population variance.

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The accompanying data table contains chest deceleration measurements (in g, where g is the force of gravity) from samples of small, midsize, and large cars. Shown are the
technology results for analysis of variance of this data table. Assume that a researcher plans to use a 0.05 significance level to test the claim that the different size categories have
the same mean chest deceleration in the standard crash test. Complete parts (a) and (b) below.
C
a. What characteristic of the data specifically indicates that one-way analysis of variance should be used?
O A. There are three samples of measurements.
O B. The measurements are categorized according to the one characteristic of size.
OC. The population means are approximately normal.
O D. Nothing specifically indicates that one-way analysis of variance should be used.
b. If the objective is to test the claim that the three size categories have the same mean chest deceleration, why is the method referred to as analysis variance?
O A. The method is based on showing that the population variances are different.
OB. The method is based on estimates of multiple varying population variances.
O C. The method is based on showing that the population variances are similar.
O D. The method is based on estimates of a common population variance.
Transcribed Image Text:The accompanying data table contains chest deceleration measurements (in g, where g is the force of gravity) from samples of small, midsize, and large cars. Shown are the technology results for analysis of variance of this data table. Assume that a researcher plans to use a 0.05 significance level to test the claim that the different size categories have the same mean chest deceleration in the standard crash test. Complete parts (a) and (b) below. C a. What characteristic of the data specifically indicates that one-way analysis of variance should be used? O A. There are three samples of measurements. O B. The measurements are categorized according to the one characteristic of size. OC. The population means are approximately normal. O D. Nothing specifically indicates that one-way analysis of variance should be used. b. If the objective is to test the claim that the three size categories have the same mean chest deceleration, why is the method referred to as analysis variance? O A. The method is based on showing that the population variances are different. OB. The method is based on estimates of multiple varying population variances. O C. The method is based on showing that the population variances are similar. O D. The method is based on estimates of a common population variance.
More Info
Chest Deceleration Measurements (g) from a Standard Crash Test
37
54
39
44
43
42
52
41
38
37
Small
Midsize
Large
44
36
32
SPSS
Sum of
Results Squares
Between 200.857
Groups
Within
Groups
Total
549.714
750.571
39
53
45
df
2
18
20
49
38
Mean Square
100.429
30.540
42
41
33
F
3.288
X
Sig.
0.061
Transcribed Image Text:More Info Chest Deceleration Measurements (g) from a Standard Crash Test 37 54 39 44 43 42 52 41 38 37 Small Midsize Large 44 36 32 SPSS Sum of Results Squares Between 200.857 Groups Within Groups Total 549.714 750.571 39 53 45 df 2 18 20 49 38 Mean Square 100.429 30.540 42 41 33 F 3.288 X Sig. 0.061
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