The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from apopulation that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below.68.48 79.88 69.17 84.87 80.59 87.41 100.62 99.59FClick the icon to view the table of critical t-values.(a) Determine a point estimate for the population mean travel taxA point estimate for the population mean travel tax is $(Round to two decimal places as needed)

We have given that data. 68.48 79.88 69.17 84.87 80.59 87.41 100.62 99.59 Sample size n =8

Answered: The accompanying data represent the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The average fruit fly will lay 421 eggs into rotting fruit. A biologist wants to see if the average wil be lower for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 429, 426, 402, 401, 393, 424, 426, 415, 416, 422, 414, 428 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use t-test for a population mean b. The alternative hypothesis would be: H: 421 c. The test statistic - -1.358 (please show your answer to 3 decimal places.) d. Based on this, we should fail to reject e. Thus, the final conclusion is that... The data suggest that the population mean number of eggs that fruit fies with this gene modified wil the null hypothesis.
An amusement park keeps track of the percentage of individuals with season passes according to age category. An independent tourist company would like to show that this distribution of age category for individuals buying season passes is different from what the amusement park claims. The tourist company randomly sampled 200 individuals entering the park with a season pass and recorded the number of individuals within each age category. Age Category Child (under 13 years old) Teen (13 to 19 years old) Adult (20 to 55 years old) Senior (56 years old and over) Number of Individuals 56 86 44 14 The tourist company will use the data to test the amusement park’s claim, which is reflected in the following null hypothesis. H0:pchild=0.23H0:pchild=0.23, pteen=0.45pteen=0.45, padult=0.20padult=0.20, and psenior=0.12psenior=0.12. What inference procedure will the company use to investigate whether or not the distribution of age category for individuals with season passes is…
State whether you would expect this distribution to be symmetric, left-skewed, orright-skewed, and briefly explain: ages of people obtaining a driver’s license for the firsttime.
List and describe at least three characteristics of the normal distribution.Find an example of something that you would expect to be normally distributed and share it. Explain why you think it it normally distributed.Find an example of something that you would not expect to be normally distributed and share it. Explain why you think it would not be normally distributed.Find a web-based resource that is helpful in understanding the Normal Distribution.
The average fruit fly will lay 389 eggs into rotting fruit. A biologist wants to see if the average will be fewer for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 358, 388, 362, 382, 371, 385, 384, 393, 403, 389, 405 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho? Select an answer♥ H₁ PS Select an answer c. The test statistic ? (please show your answer to 3 decimal
The average fruit fly will lay 377 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 367, 374, 364, 388, 407, 369, 375, 362, 403, 383, 381, 391, 371 What can be concluded at the the αα = 0.10 level of significance level of significance? The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)
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A survey was conducted two years ago asking college students their top motivations for using a credit card. To determine whether this distribution has changed, you randomly select 425 college students and ask each one what the top motivation is for using a credit card. Can you conclude that there has been a change in the claimed or expected distribution? Use a=0.10. Complete parts (a) through (d). New Survey Frequency, f 111 97 Response Old Survey % Rewards 29% 23% Low rates Cash back Discounts Other 22% 108 8% 46 18% 63 UD. XX O D. X Xo 2 OC. X >Xo OC. X>x (c) Calculate the test statistic. (Round to three decimal places as needed.) %3D (d) Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim. V the claimed or ▼enough evidence to conclude that the distribution of motivations Ho At the 10% significance level, there expected distribution.
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The accompanying histogram shows the lengths of hospital stays (in days) for all female patients admitted to a certain hospital during one year with a primary diagnosis of acute myocardial infarction (heart attack). Complete parts (a) through (c) below. a) From the histogram, determine whether the mean or median is larger. Explain. A. Because the distribution is nearly symmetric, the mean is expected to be larger than the median. B. Because the distribution is nearly symmetric, the mean is expected to be about the same as the median. C. Because the distribution is skewed to the high end, the mean is expected to be larger than the median. D. Because the distribution is skewed to the high end, the mean is expected to be smaller than the median. E. Because the distribution is skewed to the low end, the mean is expected to be larger than the median. F. Because the distribution is skewed to the low end, the mean is expected to be…

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