The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from apopulation that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below.68.48 79.88 69.17 84.87 80.59 87.41 100.62 99.59FClick the icon to view the table of critical t-values.(a) Determine a point estimate for the population mean travel taxA point estimate for the population mean travel tax is $(Round to two decimal places as needed)

We have given that data. 68.48 79.88 69.17 84.87 80.59 87.41 100.62 99.59 Sample size n =8

Answered: The accompanying data represent the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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M1
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 8. Do twenty-year-olds have a different number of cavities? The data show the results of a survey of 15 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 10, 9, 7, 10, 6, 6, 9, 11, 6, 9, 12, 10, 10, 11 What can be concluded at the αα = 0.01 level of significance? For this study, we should use t test for a population mean The null and alternative hypotheses would be: H0: Mean = __?__ H1: Mean < __?__ The test statistic t= __?__ (please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.) The p-value is >α Based on this, we should fail to reject the null hypothesis. Thus, the final conclusion is that ... Please choose one below The data suggest that the population mean number of cavities for twenty-year-olds is not significantly different…
Indicate whether the five number summary corresponds most likely to a distribution that is skewed to the left, right or symmetric (100, 110, 115, 160, 220)
The average fruit fly will lay 421 eggs into rotting fruit. A biologist wants to see if the average will be lower for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 429, 426, 402, 401, 393, 424, 426, 415, 416, 422, 414, 428 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Correct The alternative hypothesis would be: H1:H1: Correct Correct Correct The test statistic Correct = (please show your answer to 3 decimal places.) Based on this, we should Correct the null hypothesis. Thus, the final conclusion is that ... Correct
What is a skewed distribution?
An amusement park keeps track of the percentage of individuals with season passes according to age category. An independent tourist company would like to show that this distribution of age category for individuals buying season passes is different from what the amusement park claims. The tourist company randomly sampled 200 individuals entering the park with a season pass and recorded the number of individuals within each age category. Age Category Child (under 13 years old) Teen (13 to 19 years old) Adult (20 to 55 years old) Senior (56 years old and over) Number of Individuals 56 86 44 14 The tourist company will use the data to test the amusement park’s claim, which is reflected in the following null hypothesis. H0:pchild=0.23H0:pchild=0.23, pteen=0.45pteen=0.45, padult=0.20padult=0.20, and psenior=0.12psenior=0.12. What inference procedure will the company use to investigate whether or not the distribution of age category for individuals with season passes is…
Find the Z-scores that separate the middle 44% of the distribution from the area in the tails of the standard normal distribution. book 4 Player.aspx?cultureld=&theme=math&style=highered&disableStandbyIndicator=true&lassignmentHandles The Z-scores are (Use a comma to separate answers as needed. Round to two decimal places as needed.) 4 $ Click the icon to view a table of areas under the normal curve. R F F5 通道 % JUDE 5 6 T OL F6 G 1 19 F7 Y F8 H & 7 00 U J DAR F9 * 00 8 O DELL F10 K 9 Locale=true# F11 O ) L 2 F12 P PrtScr 73°F Sunny [ Insert Clear all 0 Delet Backs
The mean age of two people in a room is 20 years. A 50 year old person enters the room. What is the mean age of the 3 people in the room now 20 30 33.3 35 none of the above
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 8. Do twenty-year-olds have a different number of cavities? The data show the results of a survey of 13 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 11, 7, 6, 12, 8, 9, 10, 11, 10, 6, 8, 10, 10 What can be concluded at the αα = 0.10 level of significance? The null and alternative hypotheses would be: Please provide number H0:H0: mean = __?__ H1:H1: mean not equal to __?__ The test statistic t = __?__(please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.)
In a normal distribution, what z-score cuts off the top 65% of the distribution?a. z = 0.7422b. z = 0.2578c. z =0.39d. z = -0.39
Construct a quantile graph. Explain why or why not the data set provided has a normal distribution: 5.5, 6.0, 6.4, 5.7, 7.5, 4.5, 5.5, 5.6, 6.5, 6.0, 5.0, and 6.0. include the graph and response.
A study found that there was 48% chance that the driver fails a breathalyzer test when it is administered on a Friday night. The test is administered to 80 drivers. What distribution that can be used to model the above situation. How many drivers do we expect to fail the test

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