The accompanying data represent the ideal number of children for a random sample of 900 adults. Complete parts (a) through (d) below.Click the icon to view the data about ideal numbers of children.(a) Construct a discrete probability distribution for the random variable x.x (# of children) P(x)0.0110.0330.5780.2810.0740.0200.002(Round to three decimal places as needed.)(b) Draw a graph of the probability distribution. Choose the correct graph below.O A.O BOc.OD.OA.в.QIdeal Numberof ChildrenIdeal Numberof ChildrenIdeal Numberof ChildrenIdeal Numberof Children0.6-0.5-0.4-0.3-0.2-i 0.1-0.6-0.5-0.4-0.3-0.2-a 0.1-0.6-0.5-04-0.2-ó i2345 601234 56Number of Children012 3 4 5 6Number of Childrenói2 3 4 56Number of ChildrenNumber of Children

Answered: Image /qna-images/answer/4171e263-1c35-49fa-9103-dbcf3864f80a.jpg

Answered: The accompanying data represent the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The probability distribution below is for the random variable X = the number of credits taken during the fall semester by a randomly selected student at a large university. Calculate the mean of X. Round to the hundredths place. Credits 14 15 16 17 Probabiblity 0.05 0.65 0.20 0.10
Complete (D)
In the probability distribution to the right, the random variable X represents the number of marriages an individual aged 15 years or older has been involved in. Compute and interpret the mean of the random variable X. Hx = marriages (Type an integer or a decimal. Do not round.) X 0 1 2 3 4 5 P(x) 0.264 0.567 0.136 0.029 0.003 0.001
Determine the required value of the missing probability to make the distribution a discrete probability distribution. P(x) 3 0.21 4 0.39 6. 0.17 P(4) = (Type an integer or a decimal.)
Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 0 1 2 3 4 5 Probability 0.255 0.294 0.235 0.158 0.042 0.016 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is enter your response here. (Round to one decimal place as needed.)
K A stem-and-leaf plot for the number of touchdowns scored by all Division 1A football teams is shown below. Complete parts (a) through (c). Key: 115=15 1345788 201223457889 3001112233445577789 40012234555567889 50235578 61367 7 87 (a) If a team is selected at random, find the probability the team scored at least 30 touchdowns. (Round to three decimal places as needed.) (b) If a team is selected at random, find the probability the team scored between 40 and 49 touchdowns inclusive. (Round to three decimal places as needed.) (c) If a team is selected at random, find the probability the team scored more than 79 touchdowns. (Round three decimal places as needed.) Are any of these events unusual? Select all the unusual events below.
K The data on the right represent the number of live multiple-delivery births (three or more babies) in a particular year for women 15 to 54 years old. Use the data to complete parts (a) through (d) below. Age 15-19 20-24 25-29 30-34 35-39 40-44 45-54 Number of Multiple Births (a) Determine the probability that a randomly selected multiple birth for women 15-54 years old involved a mother 30 to 39 years old. P(30 to 39)= (Type an integer or decimal rounded to three decimal places as needed.) (b) Determine the probability that a randomly selected multiple birth for women 15-54 years old involved a mother who was not 30 to 39 years old. P(not 30 to 39) = 90 510 1622 2838 1845 373 119
The random variable X is the crew size of a randomly selected shuttle mission. Its probability distribution is shown below. Complete parts a through c. 2 5 6 7 8 D 4 0.045 0.306 P(X=x) 0.025 0.187 0.431 0.006 ... a. Find and interpret the mean of the random variable. μ= 5.947 (Round to three decimal places as needed.) Interpret the mean. Select the correct choice below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) A. The average number of persons in a shuttle crew is 5.947 person(s). OB. The most common number of persons in a shuttle crew is person(s). b. Obtain the standard deviation of the random variable. O (Round to three decimal places as needed.) Check answer Help me solve this View an example Get more help. 30 20 F10 F4 MacBook Air F6 DII FB Clear all DD F9
Use the probability distribution to complete parts (a) and (b) below. The number of school-related extracurricular activities per student Activities 0 1 2 3 4 5 6 7 Probability 0.057 0.124 0.164 0.178 0.210 0.128 0.086 0.053 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.) The variance is (Round to one decimal place as needed.) The standard deviation is (Round to one decimal place as needed.) (b) Interpret the results. The mean is so the average student is involved in (Round to one decimal place as needed.) ... The standard deviation is so the typical number of activities per student
Determine the required value of the missing probability to make the distribution a discrete probability distribution. P(x) 0.18 0.41 6 0.16 P(4) = (Type an integer or a decimal.) Enter your answer in the answer box. M Chp esc
Determine the required value of the missing probability to make the distribution a discrete probability distribution. P(x) 0.28 4 0.28 0.22 P(4) = (Type an integer or a decimal.) %3D Enter your answer in the answer box and then click Check Answer. All parts showing esc -> % 5
A survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.

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