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The acceptable level for insect filth in a certain food item is 2 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 60 ten-gram portions of the food item is obtained and results in a sample mean of x = 2.2 insect fragments per ten-gram portion. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). C... (a) Why is the sampling distribution of x approximately normal? A. The sampling distribution is approximately normal because the sample size is large enough. B. The sampling distribution is assumed to be approximately normal. C. The sampling distribution is approximately normal because the popluation is normally distributed. D. The sampling distribution is approximately normal because the population is normally distributed and the sample size is large enough. (b) What is the mean and standard deviation of the sampling distribution of x assuming μ = 2 and o= = √2? P = 2 (Round to three decimal places as needed.) = 0.183 (Round to three decimal places as needed.) (c) What is the probability a simple random sample of 60 ten-gram portions of the food item results in a mean of at least 2.2 insect fragments? P(x ≥ 2.2) = (Round to four decimal places as needed.)

The acceptable level for insect filth in a certain food item is 2 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 60 ten-gram portions of the food item is obtained and results in a sample mean of x = 2.2 insect fragments per ten-gram portion. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). C... (a) Why is the sampling distribution of x approximately normal? A. The sampling distribution is approximately normal because the sample size is large enough. B. The sampling distribution is assumed to be approximately normal. C. The sampling distribution is approximately normal because the popluation is normally distributed. D. The sampling distribution is approximately normal because the population is normally distributed and the sample size is large enough. (b) What is the mean and standard deviation of the sampling distribution of x assuming μ = 2 and o= = √2? P = 2 (Round to three decimal places as needed.) = 0.183 (Round to three decimal places as needed.) (c) What is the probability a simple random sample of 60 ten-gram portions of the food item results in a mean of at least 2.2 insect fragments? P(x ≥ 2.2) = (Round to four decimal places as needed.)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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11:57 K The acceptable level for insect filth in a certain food item is 2 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 60 ten-gram portions of the food item is obtained and results in a sample mean of x = 2.2 insect fragments per ten-gram portion. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Why is the sampling distribution of x approximately normal? A. The sampling distribution is approximately normal because the sample size is large enough. OB. The sampling distribution is assumed to be approximately normal. OC. The sampling distribution is approximately normal because the popluation is normally distributed. Vo) 1 22 ... 46 ... - 33% D. The sampling distribution is approximately normal because the population is normally distributed and the sample size is large enough. (b) What is the mean and standard deviation of the sampling distribution of x assuming μ = 2 and o √2? Hx = 2 (Round to three decimal places as needed.) ox = 0.183 (Round to three decimal places as needed.) (c) What is the probability a simple random sample of 60 ten-gram portions of the food item results in a mean of at least 2.2 insect fragments? P(x ≥ 2.2) = (Round to four decimal places as needed.) ||| = O
Transcribed Image Text:11:57 K The acceptable level for insect filth in a certain food item is 2 insect fragments (larvae, eggs, body parts, and so on) per 10 grams. A simple random sample of 60 ten-gram portions of the food item is obtained and results in a sample mean of x = 2.2 insect fragments per ten-gram portion. Complete parts (a) through (c) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Why is the sampling distribution of x approximately normal? A. The sampling distribution is approximately normal because the sample size is large enough. OB. The sampling distribution is assumed to be approximately normal. OC. The sampling distribution is approximately normal because the popluation is normally distributed. Vo) 1 22 ... 46 ... - 33% D. The sampling distribution is approximately normal because the population is normally distributed and the sample size is large enough. (b) What is the mean and standard deviation of the sampling distribution of x assuming μ = 2 and o √2? Hx = 2 (Round to three decimal places as needed.) ox = 0.183 (Round to three decimal places as needed.) (c) What is the probability a simple random sample of 60 ten-gram portions of the food item results in a mean of at least 2.2 insect fragments? P(x ≥ 2.2) = (Round to four decimal places as needed.) ||| = O
0.02 Standard Normal Distribution 0.04 0.03 0.04 0.00 0.05 0.01 0.06 0.02 Standard Normal Distribution Table (page 1) 0.4090 0.07 0.03 0.294 0.3300 0.4052 04443 0.9993 0.999% 09007 0.04 0.08 0.3264 0.4013 0.4404 0.05 09990 0.999 0.9998 0.09 0.3228 0.3974 0.06 0.3192 0.4325 0.07 0.0066 0.2810 0.3156 02807 0.4286 0.4681 0.08
Transcribed Image Text:0.02 Standard Normal Distribution 0.04 0.03 0.04 0.00 0.05 0.01 0.06 0.02 Standard Normal Distribution Table (page 1) 0.4090 0.07 0.03 0.294 0.3300 0.4052 04443 0.9993 0.999% 09007 0.04 0.08 0.3264 0.4013 0.4404 0.05 09990 0.999 0.9998 0.09 0.3228 0.3974 0.06 0.3192 0.4325 0.07 0.0066 0.2810 0.3156 02807 0.4286 0.4681 0.08
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