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The acceleration of an object that has a mass of 0.025 kg and exhibits simple harmonic motion is given by the following equation.

\[ a_x(t) = (10 \, \text{m/s}^2) \cos \left( \pi t + \frac{3\pi}{2} \right) \]

Calculate the object's velocity \( v_x(t) \) at time \( t = 4.0 \, \text{s} \), assuming that the velocity of the object is \( v_x = -3.2 \, \text{m/s} \) at \( t = 0 \, \text{s} \).

\[ v_x(4.0 \, \text{s}) = \, \boxed{} \, \text{m/s} \]

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