The acceleration after t seconds of a hawk flying along a straight path is a(t) = 0.4 +0.12t ft/s2. How much did the hawk's speed increase from t = 4 to t = 9? ft/s
The acceleration after t seconds of a hawk flying along a straight path is a(t) = 0.4 +0.12t ft/s2. How much did the hawk's speed increase from t = 4 to t = 9? ft/s
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Problem Statement:**
The acceleration after \( t \) seconds of a hawk flying along a straight path is \( a(t) = 0.4 + 0.12t \) ft/s². Determine how much the hawk's speed increased from \( t = 4 \) seconds to \( t = 9 \) seconds.
**Solution Area:**
[Text Box] ft/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fccd97de8-e10b-493c-b965-7d9287dd2ac4%2F787abf6f-8cfe-4168-9511-75536b77e5d8%2Fqqbrmlw_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
The acceleration after \( t \) seconds of a hawk flying along a straight path is \( a(t) = 0.4 + 0.12t \) ft/s². Determine how much the hawk's speed increased from \( t = 4 \) seconds to \( t = 9 \) seconds.
**Solution Area:**
[Text Box] ft/s
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