The ac voltage gain magnitude can be calculated using Eq. (10.31): Rc (47 ΚΩ) Av 2re 2(269) providing an output ac voltage of magnitude V=A,V,= (87.4)(2 mV) = 174.8 mV = 0.175 V Double-Ended AC Voltage Gain Asin How was this dition of signals applied to both in equation derived? Please answer in which can be rewritten as where V₁ = V₁₁ - Vi Common-Mode Operation of Circuit detail fferene signal Whereas a differential amplifier provides large applied to both inputs, it should also provide as small an amplification of the signal common to both inputs. An ac connection showing common input to both transors is shown in Fig. 10.18. The ac equivalent circuit is drawn in Fig. 10.19, from which we can write lb The output voltage magnitude is then = 87.4 providing a voltage gain n VoIcRc = BIRC = A = V₁ -2(3 + 1)IBRE Vo V₁ V₁ r + 2(B + 1)RE BVRC r₁ + 2(B + 1)RE con- BRC r + 2(B + 1)RE (10.6) AMI