The above graph shows the potential energy U(x) of a particle as a function of its position x. The total mechanical energy in the system is marked with the dashed horizontal line at 4 Joules. As we know, the particle has a constant total energy of 4.0 Joules, as shown by the dashed line on the graph. Based on this information, determine the kinetic energy of the particle at the following positions x = 2.0 m x = 4.0 m
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The above graph shows the potential energy U(x) of a particle as a function of its position x. The total mechanical energy in the system is marked with the dashed horizontal line at 4 Joules.
As we know, the particle has a constant total energy of 4.0 Joules, as shown by the dashed line on the graph.
Based on this information, determine the kinetic energy of the particle at the following positions
x = 2.0 m
x = 4.0 m
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- We know that the work (W) done by a force vector F applied to an object over a displacement ?x is given byW = F(cos?) ?x,where F is the magnitude of the force, and ? is the angle between the applied force and the direction of the displacement. This expression assumes that the force is constant over the displacement ?x. If F is not constant, it can be shown that the work done is equal to the area under the curve force versus position.Based on what above said, calculate the work done by the force versus position represented in each graph (a), (b), and (c) in the figure below.The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 0.250 m.) Find the work done by the force as the particle moves across the following distances. (a) from x = 0 m tox = 2.00 m(b) from x = 2.00 m to x = 3.00 m(c) from x = 0 m to x = 3.00 mA particle moves in the x-axis from x = 12.8 m to x = 23.7 m under the influence of a force where F is expressed in newtons and x is expressed in meters. Use numerical integration to determine the total work done by the force during the displacement. In the networks there are Various calculators for integrals are available.
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