The ability to taste certain substances, such as PTC is also genetically controlled. People that can taste have a dominant allele (T), while non-tasters have the recessive alleles (tt). Suppose a woman who is a non-PTC-taster has offspring with a man who is a homozygous PTC taster. What is the probability that they have a child with the tasting gene? 50% 75% O 100%

The ability to taste certain substances, such as PTC is also genetically controlled. People that can taste have a dominant allele (T), while non-tasters have the recessive alleles (tt). Suppose a woman who is a non-PTC-taster has offspring with a man who is a homozygous PTC taster. What is the probability that they have a child with the tasting gene? 50% 75% O 100%

Name: RequiredQuestion YQuestion TThe ability to taste certain substances,
Uploaded: 2024-03-20T06:42:55.000Z
Channel: Bartleby
Description: RequiredQuestion YQuestion TThe ability to taste certain substances, such as PTC isalso genetically controlled. People that can tastehave a dominant allele (T), while non-tasters havethe recessive alleles (tt). Suppose a woman who is anon-PTC-taster

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 9CT

See similar textbooks

Similar questions

Red–green color blindness is caused by an X-linked recessive genetic defect. Hence females rarely exhibit the red–green colorblind phenotype but may be carriers of the defective gene. When a narrow beam of red or green light is projected onto some areas of the retina of such a female carrier, she can readily diff erentiate the two colors, but on other areas she has diffi culty in doing so. Explain.
. In mice, the dominant allele Gs of the X-linked geneGreasy produces shiny fur, while the recessive wildtype Gs+ allele determines normal fur. The dominantallele Bhd of the X-linked Broadhead gene causesskeletal abnormalities including broad heads andsnouts, while the recessive wild-type Bhd+ alleleyields normal skeletons. Female mice heterozygousfor the two alleles of both genes were mated withwild-type males. Among 100 male progeny of thiscross, 49 had shiny fur, 48 had skeletal abnormalities,2 had shiny fur and skeletal abnormalities, and 1 waswild type.a. Diagram the cross described and calculate thedistance between the two genes.b. What would have been the results if you hadcounted 100 female progeny of the cross?
The XG locus on the human X chromosome has twoalleles, XG+ and XG. The XG+ allele causes the presence of the Xg surface antigen on red blood cells,while the recessive XG allele does not allow antigento appear. The XG locus is 10 m.u. from the STSlocus. The STS+ allele produces normal activity ofthe enzyme steroid sulfatase, while the recessive STSallele results in the lack of steroid sulfatase activityand the disease ichthyosis (scaly skin). A man withichthyosis and no Xg antigen has a normal daughterwith Xg antigen. This daughter is expecting a child.a. If the child is a son, what is the probability he willlack Xg antigen and have ichthyosis?b. What is the probability that a son would have boththe antigen and ichthyosis?c. If the child is a son with ichthyosis, what is theprobability he will have Xg antigen?
The X-linked gene responsible for DMD encodes a protein called dystrophin that is required for muscle function. Dystrophin protein is not secreted—it remains inthe cells that produce it. Given what you know aboutBarr body formation, do you think that females heterozygous for the recessive DMD disease allele could havethe disease in some parts of their bodies and not others?
The maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). How is it possible for a male homozygous for the mutationto exist?
At least two pairs of genes control eye color. Both pairs influence the production of the pigment, melanin, but act independently. One pair of alleles is B (Brown color; dominant) and b (blue color); the other pair is A (pigment production; dominant) and a (no pigment production; albino). The gene pair aais epistatic to (masks) B and b and produces the nonpigmented eyes of the albino. What is the typeof gene interaction that exists between the two gene pairs? Give the genotypes and phenotypes of the possible offspring of the mating bbAa x Bbaa andi ndicate the parental phenotypes. (any method)
Two alleles at one locus produce three distinctphenotypes. Two alleles of two genes lead tofive distinct phenotypes. Two alleles of six geneslead to 13 distinct phenotypes. (These statementsassume that the alleles at any one locus arecodominant or incompletely dominant andthat each gene makes an equal contributionto the phenotype.)a. Derive a formula to express this relationship. (Letn equal the number of genes.)b. Each of the most extreme phenotypes for a traitdetermined by two alleles at one locus are foundin a proportion of 1/4 in the F2 generation. If twoalleles of two genes determine the trait, each extreme phenotype will be present in the F2 as 1/16of the population.In common wheat (Triticum aestivum),kernel color varies from red to white andthe genes controlling the color act additively,that is, alleles for each gene are incompletelydominant and each gene contributes equallyto the color. A true-breeding red variety iscrossed to a true-breeding white variety, and1/256 of the F2…
A nectarine is a peach without the fuzz. The difference is controlledby a single gene that is found in two alleles, D and d. At themolecular level, does it make more sense to you that the nectarineis homozygous for the recessive allele or that the peach is homozygousfor the recessive allele? Explain your reasoning.
Pseudohypertrophic muscular dystrophy is an inheriteddisorder that causes gradual deterioration of the muscles. It isseen almost exclusively in boys born to apparently unaffectedparents and usually results in death in the early teens. Isthis disorder caused by a dominant or a recessive allele?Is its inheritance sex-linked or autosomal? How do youknow? Explain why this disorder is almost never seen in girls.
Two mothers give birth to sons at the same time at a busy urbanhospital. The son of mother 1 has hemophilia, a disease causedby an X-linked recessive allele. Neither parent has the disease.Mother 2 has a son without hemophilia, despite the fact thatthe father has hemophilia. Several years later, couple 1 suesthe hospital, claiming that these two newborns were swappedin the nursery following their birth. As a genetic counselor, youare called to testify. What information can you provide the juryconcerning the allegation?
is it possible to determine to genotype if an individual expressing a dominant phenotype
Rafor to the padigree below for this question. Individuais who ere sheded have an X-linked dieorder Those who ere not whaded have the normal phenetype. Let "A" snd "o" represent the dominant and receasive alieles, respectively. The disorder represented by the shaded symbol V to the normal phenotype. Dominant Recessive A list of possible genotypes is given below. Determine the appropriate genotype for each individual. Type in the number for the correct answer in the space provided. Do not type anything else in the space. It ls ok to use an answer more than one time. 1. x* Y 6. 1/2 x^ x^ + 1/2 x^ x° 7. 1/4 x^ x^ + 3/4 x^x 8. 3/4 X^ x^+ 1/4 X^ x 9. 1/3 x^ x* +2/3 x^ x 10. 2/3 x^ x^ + 1/3 x* x 2. X Y 3. X^ xA 4. XА х 5. X X The genotype of individual -5 is The genotype of individual I1-3 is The genotype of individual Il-7 is The genotype of individual IlI-3 is For the next question, give the probability as a fraction that is simplified to the lowest value. Type your fraction in #/N format…