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- Freckles are recessive. No freckles are dominate. Mom = heterozygous Dad = homozygous Possible outcomes for kids? Genotypes Phenotypes The chartThe ability to roll the tongue into a tube is a single-gene dominant trait governed by the R The recessive allele for lacking the ability is r. A woman who can roll her tongue has a father who cannot. What is her tongue-rolling genotype? RR Rr rr either A or B cannot tell from the information providedSteven has the dominant tongue rolling phenotype but does not know his genotype. His wife has the recessive non-tongue rolling trait. If their son CANNOT roll his tongue this means: O Steven has a heterozygous genotype Steven has a homozygous dominant genotype Steven has a homozygous recessive genotype o it is impossible to tell Steven's genotype from this information alone
- For the expression of a recessive trait, a person needs to inherit a Multiple Choice recessive allele from both of their parents. recessive allele from one parent and one dominate allele from the other parent. dominant allele from both of their parents.Table 7.1: Your genetic traits. Your probable genotype(s) (use only the letter combinations that apply) Your phenotype (list what you look like) Traits (alleles) Almond Straight thumbs 1. Eye shape (R, r) 2. Hitcher's Thumb (H, h) 3. Earlobes (D, d) Free 4. Interlocking Fingers (I, i) Left thumb over right Widows Peak 5. Widow's Peak (F, f) 6. Face Shape (G, g) Oval 7. Eye Color (B, b) Brown 8. Chin Shape (J, j) Round Dimples Brown 9. Dimples (A, a) 10. Hair Color (K, k) Curly 11. Hair Texture (T, t) 12. PTC Taster (Q, q)Having a widows peak is dominant W to not having one (ww)Having attached earlobes is a recessive trait (ee)- Jack and Jill are heterozygous for both traits.What's the probability of them having a child with a widow's peak and attachedearlobes?
- Person A is color blind. This has developed The person Huntington's disease. mother of person A has normal vision and does not have Huntington's disease. B does not have Person Huntington's disease and has normal vision. The mother of Person B is normal for both traits, but the father is color blind and suffers from Huntington's disease. father of person A is not color The blind or has Huntington's disease. If persons A and B what and types proportions of children would be produced considering that the disease is lethal? marry,G = green hair. g = purple hair. One parent is GG. The other parent is Gg. Which statement would be true regarding this information? Group of answer choices There is a 100% chance that their child will have green hair. One parent is green hair and the other has purple hair. Both parents have purple hair. There is a 50% chance their child will have purple hair.The genotype Gg would be an example of which? Group of answer choices Heterozygous homozygous dominant Homozygous recessive The individual’s phenotype
- When organisms reproduce and their offspring demonstrate co-dominance the offspring* dominant traits exhibit themselves CO-DOMINANCE: RED RR WHITE RRA man that can roll his tongue is heterozygous for the trait marries a woman that cannot roll her tongue. They have a child. Rolling tongue is dominant to not rolling tongue. What is the man’s genotype for tongue rolling? The woman’s? Show the Punnett square for child’s genotype Give the probability (percent chance) that the child can or cannot roll their tongue.A father has a genotype HH. A mother has a genotype hh. Which parent is homozygous recessive? Group of answer choices the mother the father both parents neither parent
