Determine the applied load P needed to cause theta = 44.6° The A-36 steel wire AB has a cross-sectional area of 11 mm2 and is unstretched when0 = 45.0° (Figure 1)Figure400 mmA0400 mmBYP<1 of 1>

The A-36 steel wire AB has a cross-sectional area (A) of 11 mm² and is unstretched when thita…

Answered: The A-36 steel wire AB has a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The 24-mm-diameter A-36 steel rod is subjected to the axial forces shown. Take E = 200 GPa. (Figure 1) Figure 600 mm B 400 mm 50 kN 50 kN C 40 kN 1 of 1 > ▾ Part A Determine the displacement of end C with respect to the fixed support at A. Express your answer to three significant figures and include the appropriate units. dc = Submit μA Value Provide Feedback Request Answer Units ? 4
25 KN Using the method that has been covered, find the displacement of the node 2 if E1 = 100 GPa and A1=10-6 m² and E2= 200 GPa and A2=2x10 6 m². N2 5 cm 2 30° N3 N1, Note: The stiffness matrix of individual elements should be first written, then the equilibrium equations at each node should be written, expanded in terms of nodal displacement, and used to perform the assembly of the global stiffness matrix of the problem. Then, the appropriate boundary conditions should be applied and the nodal displacement vector should be found. Every step should be shown; missing any step would result in point deduction even if the final answer is correct
Determine the force in each member of the loaded truss. The forces are positive if in tension, negative if in compression. Part 1 B AD 50° CD AD = Correct Answers: CD= 3.1 m The Free-Body diagram for joint Dis drawn assuming that all internal forces are in tension. Solve for the forces in AD and CD. The forces are positive if in tension, negative if in compression. 50% 50 6.2 m -3020.7586 3600 N 4699.4662 D 50° D N 3600 N N

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The A-36 steel wire AB has a cross-sectional area of 11 mm² and is unstretched when 0= = 45.0°.(Figure 1) Figure 400 mm A 0 400 mm B P 1 of 1