The 93 million Americans of age 50 and over control 50  percent of all discretionary income. AARP estimates that the average annual expenditure on restaurants and carryout food was  $1,873 for individuals in this age group. Suppose this estimate is based on a sample of 80  persons and that the sample standard deviation is $580 . Round your answers to the nearest whole numbers. a. At 99% confidence, what is the margin of error?   b. What is the 99% confidence interval for the population mean amount spent on restaurants and carryout food

Q: Find the sample size need to find the Population Mean if the margin of error is $105, the confidence…

A: Solution: From the given information, confidence level is 0.95, σ=315 and E=105.

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A: The sample size, i.e., the sampled number of people, n=8.The sample mean, x¯=$37.The sample standard…

Q: Which of the following would increase the width of a confidence interval for a population mean?

A:

Q: In a survey,  20 people were asked how much they spent on their child's last birthday gift.  The…

A: Solution: Given information: n= 20 Sample size  x= $38 Sample mean s= $7 Sample standard deviation

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A: Given The value of n is 18. The value of s is 18. The value of x=39. The confidence level is 90%.

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A:

Q: An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city…

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A: Given data, n=10 x=35 s=4 c=99%

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A:

Q: The 90  million Americans of age 50 and over control 50  percent of all discretionary income. AARP…

A: The question is about confidence interval.Given :Randomly selected no. of people ( n ) = 80Sample…

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A: We have given that  Sample size=n=23 Mean=mu=37 Standard deviation=S=4 90% confidence level

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Q: A researcher who she’s to estimate within $2 the average repair cost for a refrigerator.  if she…

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Q: In a survey, 19 people were asked how much they spent on their child's last birthday gift. The…

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Q: 1. Construct a 95% confidence interval to estimate the proportion of Wingate male students that are…

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A: Level of significance ɑ=0.25

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Q: 1. A sample size of 100 grade 9 students has a mean age of ?̅= 16 ????? and the population variance…

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Q: You work for a consumer advocate agency and want to estimate the population mean cost of replacing a…

A: According to bartleby expert guidelines we can answer only first three subparts. Rest can be repost.

Q: A researcher wishes to estimate within $5 the average repair cost of for a refrigerator.  If she…

A: Given, Margin of error = 5 Standard deviation = 15.50   Critical value: Using the z-table, the…

Q: In a survey, 27 people were asked how much they spent on their child's last birthday gift. The…

A: The mean is $36 and the standard deviation is $6.

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A: According to the given information, we have Sample mean = 39 Standard deviation, s = 16 Sample size…

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A: Introduction: The margin of error represents the maximum expected deviation between the actual…

Q: In a survey, 23 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=23sample mean (x) = 31standard deviation (s) = 8α = 1-0.95=0.05α2=0.025degrees…

Q: In a survey, 13 people were asked how much they spent on their child's last birthday gift. The…

A: From the provided information, Sample size (n) = 13 Sample mean (x̄) = 50 Sample standard deviation…

Q: The 91 million Americans of age 50 and over control 50 percent of all discretionary income. AARP…

A: a. Suppose µ is the population mean amount spent on restaurants and carryout food.

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A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.