The 7th term of the binomial (x² + y° is.... 1. О х12у12 2. О х18y8 3. О х8у18 4. О х18,18 и12

expand each expression using the Binomial Theorem

Count : a. A' + B' = b. A - B' = c. A'B =

(x3y4z6)7/(x6y4z)6=yrzs/xt Finding the values of r,s,t which are exponents. I am able to expand till y4z36/x15=yrzs/xt.I am kind of stuck here as I don't understand how I would be able to find the values in numeric term.

Determine the coefficient of a10 in (1 - За5)7 by completing the following given steps. Vir die a 10 term: For the a10 term: [4]r = 3 = r = [5] = (i5)(-1)15[3]51 = [6]. А. В. С. D. -3a (3a)5 (-3a)5 Е. F. G. За | За5 -3a5

Write the expression as a single loganthm with coefficient 1. As with a!=1 and b!=1. 2log_(a)2-8log_(a)y^(2)

Do this

5. Determine whether or not the expression is satisfiable. (x1 VT2 Vx3)^(x₁Vx2 VT3) A(T₁ VT2 VT3)

The expansion of (1- x)® = A 1+ 4x - 7x² + . . B 1-4x +7x2 C 1+ 4x - 7x2 +. Đ 1-4x + 7x2 - 23. – .

5 2 4 (02 4 5 2 C = -2 4 D= -6 -6 --(-) --(9) 5 A = 65 B = 5 5 3 4 1 2 -1 10-3 -2 4-2) Find the following expression: 1. 2A + 4B 2.0A + B 1.5 (9) -3.0 u= 4 -2 31 A ^ = (-²2² 7²²9) 1 6 1 2 2, 3. 0.4B-4.2A Find the following expression: 1. AB 2. ABT V= 3 By definition, forces are in equilibrium if their resultant is the zero vector. Find a force p such that the above u, v, w, and p are in equilibrium.. 1 -3 +679 B = -3 1 0 0 4. 3A + 0.5B + C -5 W = -30 10