The 75 kg student in (Figure 1) balances a 1200 kg elephant on a hydraulic lift. For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Figure 1 of 1 Part B When a second student joins the first, the height difference between the liquid levels in the right and left pistons is 35 cm. What is the second student's mass? Express your answer with the appropriate units. ► View Available Hint(s) m = 56.5 μА kg ?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Note: 54.9 kg and 56.5 kg are not the correct answers given to me by previous tutors. Could I please be given the correct answer?

**Educational Exercise on Hydraulic Lift**

A 75 kg student is depicted balancing a 1200 kg elephant on a hydraulic lift. This scenario illustrates the principle of hydraulic balance and pressure.

- **Figure Explanation:**
  The figure shows a hydraulic lift system. The student is on the left piston, and the elephant is on the right. Both pistons are submerged in oil, with a distance of 2.0 meters between them. This setup is used to demonstrate the balance of forces in a hydraulic system.

- **Problem Statement (Part B):**
  When a second student joins the first, the liquid levels' height difference between the right and left pistons is 35 cm. The task is to determine the mass of the second student.
  
  You need to express your answer with the appropriate units.

- **Current Calculation Attempt:**
  An attempt was made to calculate the mass of the second student as 56.5 kg, which was marked incorrect. There are 2 attempts remaining.

For assistance with calculations, consider reviewing:
- [Rearrangement of Equations Involving Multiplication and Division](#)

Use this exercise to understand hydraulic systems and practice equation rearrangement.
Transcribed Image Text:**Educational Exercise on Hydraulic Lift** A 75 kg student is depicted balancing a 1200 kg elephant on a hydraulic lift. This scenario illustrates the principle of hydraulic balance and pressure. - **Figure Explanation:** The figure shows a hydraulic lift system. The student is on the left piston, and the elephant is on the right. Both pistons are submerged in oil, with a distance of 2.0 meters between them. This setup is used to demonstrate the balance of forces in a hydraulic system. - **Problem Statement (Part B):** When a second student joins the first, the liquid levels' height difference between the right and left pistons is 35 cm. The task is to determine the mass of the second student. You need to express your answer with the appropriate units. - **Current Calculation Attempt:** An attempt was made to calculate the mass of the second student as 56.5 kg, which was marked incorrect. There are 2 attempts remaining. For assistance with calculations, consider reviewing: - [Rearrangement of Equations Involving Multiplication and Division](#) Use this exercise to understand hydraulic systems and practice equation rearrangement.
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