8:37 ll ? EPractice Assignment...2/11..GENERAL FRICTION PROBLEMSQ.1(379 N; towards left)The 700-N force is applied to the 100-kg block,which is stationary before the force is applied. De-termine the magnitude and direction of the frictionforce F exerted by the horizontal surface on theblock.P= 700 N100 kg30°H, = 0.80H = 0.60Q.2(66 N; 516 N; 148.5 N)The coefficients of static and kinetic friction be-tween the 100-kg block and the inclined plane are0.30 and 0.20, respectively. Determine (a) the fric-tion force F acting on the block when P is appliedwith a magnitude of 200 N to the block at rest,(b) the force P required to initiate motion up the in-cline from rest, and (c) the friction force F acting onthe block if P = 600 N.P100 kg20°4, = 0.30H = 0.2015°

We know that we have given that the force on a block is 700 N applied with an angle of 30o with the…

The 700-N force is applied to the 100-kg block, which is stationary before the force is applied. De- termine the magnitude and direction of the friction force F exerted by the horizontal surface on the block.

The 700-N force is applied to the 100-kg block, which is stationary before the force is applied. De- termine the magnitude and direction of the friction force F exerted by the horizontal surface on the block.

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8:37 ll ? E
Practice Assignment...
2/11
..
GENERAL FRICTION PROBLEMS
Q.1
(379 N; towards left)
The 700-N force is applied to the 100-kg block,
which is stationary before the force is applied. De-
termine the magnitude and direction of the friction
force F exerted by the horizontal surface on the
block.
P= 700 N
100 kg
30°
H, = 0.80
H = 0.60
Q.2
(66 N; 516 N; 148.5 N)
The coefficients of static and kinetic friction be-
tween the 100-kg block and the inclined plane are
0.30 and 0.20, respectively. Determine (a) the fric-
tion force F acting on the block when P is applied
with a magnitude of 200 N to the block at rest,
(b) the force P required to initiate motion up the in-
cline from rest, and (c) the friction force F acting on
the block if P = 600 N.
P
100 kg
20°
4, = 0.30
H = 0.20
15°

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