The 6-ft wall shown here stands 22 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall. Beam Building 6' wall 22'
The 6-ft wall shown here stands 22 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall. Beam Building 6' wall 22'
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The text reads:
"The 6-ft wall shown here stands 22 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall."
Diagram explanation:
- The diagram is a side view of a scenario involving a wall and a building.
- There is a 6-foot tall wall positioned 22 feet away from the building.
- A beam is depicted as a diagonal line extending from the top of the wall to the side of the building.
"Let x be the distance between the bottom of the wall and the point at which the beam touches the ground. Express the length of the beam in terms of x.
\( L(x) = \sqrt{x^2 + 36} \left(1 + \frac{22}{x}\right) \)
The length of the shortest beam is [ ] ft.
(Round to the nearest tenth as needed.)"](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff7a2219d-e88b-43ff-9d7f-5d8420e02742%2Ff1a0274e-7f71-4ffc-bed8-52b81ba3f71c%2F0xckkon_processed.png&w=3840&q=75)
Transcribed Image Text:The text reads:
"The 6-ft wall shown here stands 22 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall."
Diagram explanation:
- The diagram is a side view of a scenario involving a wall and a building.
- There is a 6-foot tall wall positioned 22 feet away from the building.
- A beam is depicted as a diagonal line extending from the top of the wall to the side of the building.
"Let x be the distance between the bottom of the wall and the point at which the beam touches the ground. Express the length of the beam in terms of x.
\( L(x) = \sqrt{x^2 + 36} \left(1 + \frac{22}{x}\right) \)
The length of the shortest beam is [ ] ft.
(Round to the nearest tenth as needed.)"
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