The 5th percentile of the chi-squared distributionwith n 5 10
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The 5th percentile of the chi-squared distribution
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- The time spent (in days) waiting for a heart transplant in two states for patients with type A+ blood can be approximated by a normal distribution, as shown in the graph to the right. Complete parts (a) and (b) below. u=122 o= 21.4 (a.) What is the shortest time spent waiting for a heart that would still place a patient in the top 25% of waiting times? _____ days (Round to two decimal places as needed.) (b.) What is the longest time spent waiting for a heart that would still place a patient in the bottom 20% of waiting times? ______ days (Round to two decimal places as needed.)The degrees of freedom determine the _____ the t distribution? a. mean of b. variance of c. shape of d. range ofQ4: find the mean, the model, the variance and the standard deviation for the frequency distribution of profit where the data is represented the number of (35) product that sold during one day? Class limits frequency 13-19 2 20-26 7 27-33 12 34-40 5 41-47 6. 48-54 1 55-61 62-68 2
- t8 solve both pleaseFor the distribution as shownDetermine the 3rd quartile Class. f3-6 46-9 109-12 1212-15 915-18 5TEN Suppose that the time required to complete a 1040R tax form is normal distributed with a mean of 110 minutes and astandard deviation of 15 minutes. What proportion of 1040R tax forms will be completed in less than 106 minutes? Round your answer to at least four decimal places.
- Normal Distribution The following table shows the temperature at noon on February 21, 2018 in 5 different Canadian cities. Calculate the z-score for each temperature measurement, and find which city was experiencing the most "exceptional" (out-of-ordinary) temperature on that day. City Temp. on February 21 Average Temp. in February Std. Deviation z-score Montreal 3.4 -7.7 2.7 Toronto 3.2 -4.5 2.3 Vancouver -3.3 4.9 1.5 Regina -27 -11.7 4.2 Halifax 5.4 -5.2 2 The city with the most "exceptional" (out-of-ordinary) temperature on that day is choose: -Montreal -Toronto -Vancouver -Regina -HalifaxA test of the claim that the proportion of residents with that least two jobs is more than 53% produces the test statistic z = 1.68 Find the P-value.5 Use the table below to find the percentage of data items in a normal distribution that lie a. below and b. above a z-score of −2.1. z-score -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 Percentile 0.13 0.19 0.26 0.35 0.47 0.62 0.82 1.07 1.39 1.79 z-score -2.0 -1.9 -1.8 -1.7 -1.6 -1.5 -1.4 -1.3 -1.2 -1.1 Percentile 2.28 2.87 3.59 4.46 5.48 6.68 8.08 9.68 11.51 13.57 z-score -1.0 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 Percentile 15.87 18.41 21.19 24.20 27.43 30.85 34.46 38.21 42.07 46.02 a. The percentage of data items that lie below the z-score is ___%. b. The percentage of data items that lie above the z-score is ___%
