The 50-mm-diameter solid shaft is made of 2014-T6 aluminum andis subjected to the distributed and concentrated torsional loadingsshown where T = 1.75 kN·m. (Figure 1)Part AFigureB0.4 mT2 kN·m/m0.6 m1 of 1Determine the angle of twist at the free end A of the shaft.Express your answer in degrees to three significant figures.ΜΕ ΑΣΦvec|= 1.89SubmitPrevious Answers Request Answer× Incorrect; Try Again; 23 attempts remaining< Return to AssignmentProvide Feedback?

Answered: The 50-mm-diameter solid shaft is made…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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QUESTION 1 The assembly consists of two rods and a horizontal bar BC. Each of the rod AB and CD is made of aluminum and has a cross-sectional area of 125 mm2. A point lqad of 5 kN is applied at point E were located 0.20 m from B. Knowing that they support the rigid member BC, calculate the deflection of point E. Modulus of elasticity for aluminium is 75 GPa. P- 5 kN 0.36 m E B C 0.44 m 0.20 m
The fixture shown in Figure 5 is fixed at point A and free at point C. The frame is made from a steel bar 50 mm wide and 75 mm thick. Assuming Young's modulus for steel to be 200 GPa, determine the vertical deflection at C due to the applied load of 5 kN. Use Castigliano's theorem and ignore any axial or shear deformations. A 4.5 m Figure 5 kN с T B 5 (not to sca 1.5 m Cross section ↓ 0 ↑ h b = 50 mm = 75 mm
The cantilever beam shown is an aluminum pipe that has an outside diameter of 114 mm and an inside diameter of 97.3 mm. A moment of 3 kN-m is applied at the free end. Find the rotation at the free end of the pipe. Neglect the weight of the pipe. М 33KN.m 2m Mod. of Mod. of Coeff, of Elasticity Rigidity G Thermal Ultimate Strength Density kg /m3 x 10 Tensile Yield Strength F, MPa Expansion a m/m/C x 10-6 Poisson's MPa MPa MPa Ratio Material x 10 x 10 Tens. Comp. Shear Steel ASTM A36 or A501 7.85 207 83 250 400 11.7 0.25 Steel (high-strength low-alloy) ASTM A992 7.85 207 83 345 450 11.7 0.25 Steel AISI 1020 hot-rolled 7.85 207 79.3 210 380 11.7 0.25 Steel AISI 1040 hot-rolled 7.85 207 79.3 290 520 11.7 0.25 Stainless steel 7.85 200 80 280 580 410 11.7 0.25 (annealed) Cast iron (gray) 7.21 103 41 140 550 220 10.6 0.26 Aluminum allov 2.64 70 28 240 260 190 23.6 0.33 6061-T6 Magnesium alloy 1.794 45 17 210 280 140 26.1 0.34 Titanium alloy 4.40 114 45 900 970 690 9.7 Nominal Outside Inside…
A hollow shaft made of red-brass copper (G = 37 GPa, shear yield strength = 150 MPa) is sandwiched between two solid shafts made of the same material. End A is fixed to a rigid wall and torques are applied to the shaft as shown. 75 kNm d₂160 kNm A d₁ L₁ B Use the following values in your working out: L₂ L₁ = 1.5 m L3 = 2.2 m d₁ = 1 m d₂ = 0.7 m d3 = 1.2 m C d₂ 3 L3 130 kNm D a) Draw a torque diagram for the entire shaft. b) Determine the maximum allowable inner diameter for the hollow section of the shaft, to the nearest mm. c) Determine the maximum length of L₂ (to the nearest mm) that will ensure the angle of twist of D relative to the wall is less than 2°. Use your value from part b for the inner diameter of the hollow shaft. d) By estimating relevant load(s), dimensions, and material properties, calculate the approximate angle of twist between two (non-coincident) points on the object shown below. Clearly state all assumptions, including the location of the chosen points.
A two pinned end bars AB (Copper), ? = 850 ??2, ? = 120 ??? and BC (Aluminum), ? = 1000??2, ? = 70 ??? is subjected to a horizontal force of 100 ?? applied at pin B as shown in the figure, determine the horizontal displacement of pin B.
Solve the angle of twist on a solid shaft, with Scm radius and 50cm length, if the torque applied is 2MN-mm. The modulus of rigidity is 50000MPA. O 0.204rad O 0.0204rad O 0.00204rad O 0.000204rad
T' T An aluminum alloy shaft has an allowable shear stress of Tallow= 100MPa. If the diameter of the shaft is 100 mm and a 75 mm diameter hole were bored through the shaft, determine the maximum torque T that can be transmitted. Give your answer in N.m.
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DYNAMICS OF RIGID BODIES problem Show complete solution.
3:30 51 Photo Done Problem 1: A round solid shaft is subjected to torsion as shown. Find: 1- Maximum torsional shear stress of the steel and aluminum shafts. 2-Angle of twist at point C. Steel G = 30.0x106 psi 3" Radius Steel 2" Radius Aluminum π/ DA Aluminum G = 15.0x105 psi A B T₁ = 50 k-ft T₂ = 20 k-ft 8 ft 12 ft + T2 +
TD= 657.03 N.M

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