The 38-kg crate is projected down an incline as shown with an initial speed of 7.5 m/s. Investigate the time t required for the crate to come to rest and the corresponding distance x traveled if e = 11.8°. What is the largest angle e for which the block will stop? =7.5 m/s 38 kg H4 = 0.40 Answers m e = 11.8°, t - 8max =
The 38-kg crate is projected down an incline as shown with an initial speed of 7.5 m/s. Investigate the time t required for the crate to come to rest and the corresponding distance x traveled if e = 11.8°. What is the largest angle e for which the block will stop? =7.5 m/s 38 kg H4 = 0.40 Answers m e = 11.8°, t - 8max =
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![The 38-kg crate is projected down an incline as shown with an initial speed of 7.5 m/s. Investigate the time t required for the crate to come to rest and the corresponding distance x
traveled if e = 11.8°. What is the largest angle e for which the block will stop?
o = 7.5 m/s
38 kg
He = 0.40
Answers
e = 11.8°, t =
emax =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0502167-0801-440e-9fb1-b78bd8cdda42%2F751e20b3-b40a-43df-85e0-2c038ec88d19%2Fazvvmst_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The 38-kg crate is projected down an incline as shown with an initial speed of 7.5 m/s. Investigate the time t required for the crate to come to rest and the corresponding distance x
traveled if e = 11.8°. What is the largest angle e for which the block will stop?
o = 7.5 m/s
38 kg
He = 0.40
Answers
e = 11.8°, t =
emax =
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