The 379-kg (MA) and 265-kg (mg) mine cars are rolling in opposite directions along the horizontal track with the respective speeds of 0.37 m/s (VA) and 0.46 m/s (vg). Upon impact the cars become coupled together. Just prior to impact, a 141-kg boulder leaves the delivery chute with a velocity of v= 1.24 m/s in the direction shown and lands in the 379-kg car. Calculate the velocity v₁ of the system after the boulder has come to rest relative to the car. Also, calculate the final velocity v₂ if the cars were coupled before the boulder dropped. The velocities are positive if to the right, negative if to the left. Assume = 35°. 8 Answers: V1 = V2 MA i i 0 VB O m/s m/s
The 379-kg (MA) and 265-kg (mg) mine cars are rolling in opposite directions along the horizontal track with the respective speeds of 0.37 m/s (VA) and 0.46 m/s (vg). Upon impact the cars become coupled together. Just prior to impact, a 141-kg boulder leaves the delivery chute with a velocity of v= 1.24 m/s in the direction shown and lands in the 379-kg car. Calculate the velocity v₁ of the system after the boulder has come to rest relative to the car. Also, calculate the final velocity v₂ if the cars were coupled before the boulder dropped. The velocities are positive if to the right, negative if to the left. Assume = 35°. 8 Answers: V1 = V2 MA i i 0 VB O m/s m/s
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![The 379-kg (MA) and 265-kg (mg) mine cars are rolling in opposite directions along the horizontal track with the respective speeds of
0.37 m/s (VA) and 0.46 m/s (vg). Upon impact the cars become coupled together. Just prior to impact, a 141-kg boulder leaves the
delivery chute with a velocity of v = 1.24 m/s in the direction shown and lands in the 379-kg car. Calculate the velocity v₁ of the system
after the boulder has come to rest relative to the car. Also, calculate the final velocity v₂ if the cars were coupled before the boulder
dropped. The velocities are positive if to the right, negative if to the left.
Assume = 35°.
8
AA
MA
30 0
Answers:
V1 =
V2 =
i
i
MB
コロ
m/s
m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff65cb61b-76eb-4d44-99c8-c9472014cdc8%2F902a7ae6-3f6d-41df-8cd9-0b6c3c5eea30%2Fansofmd_processed.png&w=3840&q=75)
Transcribed Image Text:The 379-kg (MA) and 265-kg (mg) mine cars are rolling in opposite directions along the horizontal track with the respective speeds of
0.37 m/s (VA) and 0.46 m/s (vg). Upon impact the cars become coupled together. Just prior to impact, a 141-kg boulder leaves the
delivery chute with a velocity of v = 1.24 m/s in the direction shown and lands in the 379-kg car. Calculate the velocity v₁ of the system
after the boulder has come to rest relative to the car. Also, calculate the final velocity v₂ if the cars were coupled before the boulder
dropped. The velocities are positive if to the right, negative if to the left.
Assume = 35°.
8
AA
MA
30 0
Answers:
V1 =
V2 =
i
i
MB
コロ
m/s
m/s
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