For the procedure, the options are on the second screenshot. The 2002 general Social Survey asked a large number of people how much time they spent watching TVeach day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sampleof 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population ofTV watching times is normally distributed. Under 10% significance level can you conclude that thepopulation standard deviation of TV watching times for teenagers is different from 2.23?Procedure: Select an answerAssumption Select an answerO PopuO The One proportion Z Hypothesis Testbonses are both greater than 10O PopuOne variance x Hypothesis TestO SimpO Norm One mean T Hypothesis TestO SamdOne mean Z Hypothesis TestStep 1. Hypue opwhere ? v is theHp: Select an answer v =Select an answervand the units are? vHa: Select an answer v?vand the test is Select an answer vStep 2. The significance level a =Step 3. Compute the value of the test statistic: Select an answer v(Round the answer to 3decimal places)Step 4. Testing Procedure: (Round the answers to 3 decimal places)CVAPVACompute the P-value of the teststatistic:Provide the critical value(s) for the Rejection Region:left CV isand right CV isP-value isStep 5. Decision:CVAPVAIs the test statistic in the rejection region?Is the P-value less than the significance level?Conclusion: Select an answerStep 6. Interpretation: The 2002 general Social Survey asked a large number of people how much time they spent watching TVeach day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sampleof 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population ofTV watching times is normally distributed. Under 10% significance level can you conclude that thepopulation standard deviation of TV watching times for teenagers is different from 2.23?Procedure: Select an answerAssumptions: (select everything that applies)O Population standard deviation is knownO The number of positive and negative responses are both greater than 10O Population standard deviation is unknownO Simple random sampleO Normal populationO Sample size is greater than 30Step 1. Hypotheses Set-Up:where ? v is theSelect an answerHọ: Select an answer v=vand the units areH: [Select an answer vand the test is Select an answer vStep 2. The significance level a =56Step 3. Compute the value of the test statistic: Select an answer v=(Round the answer to 3decimal places)Step 4. Testing Procedure: (Round the answers to 3 decimal places)CVAPVACompute the P.value of the testProvide the critical value(s) for the Rejection Region:statistic::left CV isand right CV isP-value isStep 5. Decision:CVAPVAIs the test statistic in the rejection region?Is the P-value less than the significance level?Conclusion: [Select an answerStep 6. Interpretation:

Name: For the procedure, the options are on the second screenshot. The 2002
Uploaded: 2024-03-20T06:38:44.000Z
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Description: For the procedure, the options are on the second screenshot. The 2002 general Social Survey asked a large number of people how much time they spent watching TVeach day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that

here we use χ2 one variance test given mean 4.16 standard deviation 2.23

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Statistics

The 2002 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of TV watching times is normally distributed. Under 10% significance level can you conclude that the population standard deviation of TV watching times for teenagers is different from 2.23? Procedure: Select an answer Assumption Select an answer O Popu O The One proportion Z Hypothesis Test ponses are both greater than 10 O Popu One variance x" Hypothesis Test O Simp O Norm One mean T Hypothesis Test O Samg One mean Z Hypothesis Test Step 1. Hypl

The 2002 general Social Survey asked a large number of people how much time they spent watching TV each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of TV watching times is normally distributed. Under 10% significance level can you conclude that the population standard deviation of TV watching times for teenagers is different from 2.23? Procedure: Select an answer Assumption Select an answer O Popu O The One proportion Z Hypothesis Test ponses are both greater than 10 O Popu One variance x" Hypothesis Test O Simp O Norm One mean T Hypothesis Test O Samg One mean Z Hypothesis Test Step 1. Hypl

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Statements and Logic

Logic is the analysis of general patterns of thoughts without regard to any specific sense of context.

Topic Video

Question

For the procedure, the options are on the second screenshot.

The 2002 general Social Survey asked a large number of people how much time they spent watching TV
each day. The mean number of hours was 4.16 with a standard deviation of 2.23. Assume that in a sample
of 52 teenagers, the sample standard deviation of daily TV time is 1.98 hours, and that the population of
TV watching times is normally distributed. Under 10% significance level can you conclude that the
population standard deviation of TV watching times for teenagers is different from 2.23?
Procedure: Select an answer
Assumption Select an answer
O Popu
O The One proportion Z Hypothesis Test
bonses are both greater than 10
O Popu
One variance x Hypothesis Test
O Simp
O Norm One mean T Hypothesis Test
O Samd
One mean Z Hypothesis Test
Step 1. Hypue op
where ? v is the
Hp: Select an answer v =
Select an answer
vand the units are
? v
Ha: Select an answer v?v
and the test is Select an answer v
Step 2. The significance level a =
Step 3. Compute the value of the test statistic: Select an answer v
(Round the answer to 3
decimal places)
Step 4. Testing Procedure: (Round the answers to 3 decimal places)
CVA
PVA
Compute the P-value of the test
statistic:
Provide the critical value(s) for the Rejection Region:
left CV is
and right CV is
P-value is
Step 5. Decision:
CVA
PVA
Is the test statistic in the rejection region?
Is the P-value less than the significance level?
Conclusion: Select an answer
Step 6. Interpretation:

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