The 1989 U.S. Open golf tournament was played on the East Course of the Oak Hills Country Club in Rochester, New York. During second round, four golfers scored a hole in one on the par 3 sixth hole. The odds of a professional golfer making a hole in one are estimated to be 3,708 to 1, so the probability is 1/3,709. There were 175 golfers participating in the second round that day. a. What is the probability that no one gets a hole in one on the sixth hole? (Round your answer to 5 decimal places.) Probability b. What is the probability that exactly one golfer gets a hole in one on the sixth hole? (Round your answer to 5 decimal places.) Probability c. What is the probability that four golfers score a hole in one on the sixth hole? (Round your answer to 3 decimal places.) Probability

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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The 1989 U.S. Open golf tournament was played on the East Course of the Oak Hills Country Club in Rochester, New York. During the second round, four golfers scored a hole in one on the par 3 sixth hole. The odds of a professional golfer making a hole in one are estimated to be 3,708 to 1, so the probability is 1/3,709. There were 175 golfers participating in the second round that day.

**Questions:**

**a.** What is the probability that no one gets a hole in one on the sixth hole? *(Round your answer to 5 decimal places.)*

- **Probability**: [Input box]

**b.** What is the probability that exactly one golfer gets a hole in one on the sixth hole? *(Round your answer to 5 decimal places.)*

- **Probability**: [Input box]

**c.** What is the probability that four golfers score a hole in one on the sixth hole? *(Round your answer to 3 decimal places.)*

- **Probability**: [Input box]

Note: Calculations for probabilities can be done using the binomial distribution formula, where the number of trials is 175, and the probability of success (a hole in one) is 1/3,709.
Transcribed Image Text:The 1989 U.S. Open golf tournament was played on the East Course of the Oak Hills Country Club in Rochester, New York. During the second round, four golfers scored a hole in one on the par 3 sixth hole. The odds of a professional golfer making a hole in one are estimated to be 3,708 to 1, so the probability is 1/3,709. There were 175 golfers participating in the second round that day. **Questions:** **a.** What is the probability that no one gets a hole in one on the sixth hole? *(Round your answer to 5 decimal places.)* - **Probability**: [Input box] **b.** What is the probability that exactly one golfer gets a hole in one on the sixth hole? *(Round your answer to 5 decimal places.)* - **Probability**: [Input box] **c.** What is the probability that four golfers score a hole in one on the sixth hole? *(Round your answer to 3 decimal places.)* - **Probability**: [Input box] Note: Calculations for probabilities can be done using the binomial distribution formula, where the number of trials is 175, and the probability of success (a hole in one) is 1/3,709.
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