The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x-direction. A golfer hits his tee shot a distance of 200.0 m, corresponding to a displacement Ar, = 200.0 m î, and hits his second shot 190.1 m with a displacement Ar, = 170.0 m î + 85.0 m j. What is the final displacement of the golf ball from the tee (in m)? (Express your answer in vector form.) Ar.. "total = m

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x-direction. A golfer hits his tee shot a distance of 200.0 m, corresponding
to a displacement Ar,
200.0 m î, and hits his second shot 190.1 m with a displacement Ar,
170.0 m î + 85.0 m j. What is the final displacement of the golf ball from the tee (in m)? (Express your
%3D
%3D
answer in vector form.)
Ar.
total
m
Transcribed Image Text:The 18th hole at Pebble Beach Golf Course is a dogleg to the left of length 496.0 m. The fairway off the tee is taken to be the x-direction. A golfer hits his tee shot a distance of 200.0 m, corresponding to a displacement Ar, 200.0 m î, and hits his second shot 190.1 m with a displacement Ar, 170.0 m î + 85.0 m j. What is the final displacement of the golf ball from the tee (in m)? (Express your %3D %3D answer in vector form.) Ar. total m
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Step 1

Solution:

Given that

golfer hits his tee shot a distance of 200 m, corresponding to a displacemen r1=200 m i^

hits his second shot 189.0 m with a displacement r1=170 m i ^+85 j^

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