The 125 mm x 38 mm F22 unseasoned Tallowwood (hardwood) truss bottom chord tension member shown in Figure 1 supports a roof in a domestic dwelling in Brisbane, Queensland. The length of the member is 2.4 metres, with 4 M10 bolts in rows of two connecting each end. Diameter of the bolt holes are 11mm. The member is subject to the following (unfactored) tensile loads: * Permanent actions G = 5.0 kN * Imposed actions (construction loads) Qconst = 3.5 kN * Ultimate wind actions (downwards) Wu = 17 kN giving tension in the bottom chord Calculate the tensile capacity (Not) in accordance with AS 1720.1 and check against each of the three loading combinations below. (a) Permanent actions 1.35G (b) 5 day loading (construction loading) 1.2G + 1.5Q (c) Ultimate wind actions (downwards) 1.2G + Wu 2.4 m Figure 2
The 125 mm x 38 mm F22 unseasoned Tallowwood (hardwood) truss bottom chord tension member shown in Figure 1 supports a roof in a domestic dwelling in Brisbane, Queensland. The length of the member is 2.4 metres, with 4 M10 bolts in rows of two connecting each end. Diameter of the bolt holes are 11mm. The member is subject to the following (unfactored) tensile loads: * Permanent actions G = 5.0 kN * Imposed actions (construction loads) Qconst = 3.5 kN * Ultimate wind actions (downwards) Wu = 17 kN giving tension in the bottom chord Calculate the tensile capacity (Not) in accordance with AS 1720.1 and check against each of the three loading combinations below. (a) Permanent actions 1.35G (b) 5 day loading (construction loading) 1.2G + 1.5Q (c) Ultimate wind actions (downwards) 1.2G + Wu 2.4 m Figure 2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The 125 mm x 38 mm F22 unseasoned Tallowwood (hardwood) truss bottom chord tension
member shown in Figure 1 supports a roof in a domestic dwelling in Brisbane, Queensland.
The length of the member is 2.4 metres, with 4 M10 bolts in rows of two connecting each
end. Diameter of the bolt holes are 11mm.
The member is subject to the following (unfactored) tensile loads:
* Permanent actions G = 5.0 kN
* Imposed actions (construction loads) Qconst = 3.5 kN
* Ultimate wind actions (downwards) Wu = 17 kN giving tension in the bottom chord
Calculate the tensile capacity (Not) in accordance with AS 1720.1 and check against each of
the three loading combinations below.
(a) Permanent actions 1.35G
(b) 5 day loading (construction loading) 1.2G + 1.5Q
(c) Ultimate wind actions (downwards) 1.2G + Wu
2.4 m
Figure 2
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