The 10-kg rod AB is pin-connected at A and subjected to a couple moment of M-15 Nm. The spring connecting CB is unstretched when the rod is at 0-30°. As the rod rotates, the spring always remains horizontal, because of the roller support at C. The mass moment of inertia of the rod about A is la- 1.875 kg.m2. It was observed, when the rod is released from rest at 8-30° and falls at 8 = 60°, its angular velocity w increases from 0 to 4.5 rad/s. Determine the spring stiffness constant k. = C A Ⓒk-40 Nm k-62 Nm k-85 Nm k M= 15 N m k-100 Nm B 0.75 m
The 10-kg rod AB is pin-connected at A and subjected to a couple moment of M-15 Nm. The spring connecting CB is unstretched when the rod is at 0-30°. As the rod rotates, the spring always remains horizontal, because of the roller support at C. The mass moment of inertia of the rod about A is la- 1.875 kg.m2. It was observed, when the rod is released from rest at 8-30° and falls at 8 = 60°, its angular velocity w increases from 0 to 4.5 rad/s. Determine the spring stiffness constant k. = C A Ⓒk-40 Nm k-62 Nm k-85 Nm k M= 15 N m k-100 Nm B 0.75 m
Related questions
Question
Ggg
Transcribed Image Text:The 10-kg rod AB is pin-connected at A and subjected to a couple moment of M-15 Nm. The spring
connecting CB is unstretched when the rod is at 0-30°. As the rod rotates, the spring always remains
horizontal, because of the roller support at C. The mass moment of inertia of the rod about A is la-
1.875 kg.m². It was observed, when the rod is released from rest at 0-30° and falls at 0= 60°%, its
angular velocity w increases from 0 to 4.5 rad/s. Determine the spring stiffness constant k.
C
A
Ⓒk-40 Nm
k-62 Nm
k-85 Nm
k
www.
M= 15 N m
k-100 Nm
0.75 m
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
