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expected, draw both enantiomers. Note H₂C- KMnO4 NaOH, cold OH OH

expected, draw both enantiomers. Note H₂C- KMnO4 NaOH, cold OH OH

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the major product?

The image displays a chemical reaction. **Chemical Reaction:** - The starting material is a cyclohexene ring with a methyl group attached to it. - The reaction conditions are specified as potassium permanganate (KMnO₄) in the presence of sodium hydroxide (NaOH), under cold conditions. **Process:** - This represents an oxidation reaction where KMnO₄, a strong oxidizing agent, is used to oxidize the compound. - Typically, under cold, basic conditions, KMnO₄ can convert alkenes to diols (vicinal diols), adding hydroxyl groups across the double bond. This setup is commonly used in organic chemistry to demonstrate the synthesis of glycols from alkenes.
Transcribed Image Text:The image displays a chemical reaction. **Chemical Reaction:** - The starting material is a cyclohexene ring with a methyl group attached to it. - The reaction conditions are specified as potassium permanganate (KMnO₄) in the presence of sodium hydroxide (NaOH), under cold conditions. **Process:** - This represents an oxidation reaction where KMnO₄, a strong oxidizing agent, is used to oxidize the compound. - Typically, under cold, basic conditions, KMnO₄ can convert alkenes to diols (vicinal diols), adding hydroxyl groups across the double bond. This setup is commonly used in organic chemistry to demonstrate the synthesis of glycols from alkenes.
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That answer is incorrect. Is there another possible solution? Preferably in a cyclopentane shape

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