Textbook Problem Graph each of the following from x = 0 to x = 2x. y = 1- 2sin 2x The answer in the back of the book says the answer is y=cos4x which is what I got too. But bartleby says it's: Concept Involved: We need to rewrite the given function using the double angle identity, and then graph it in the given interval. Calculation: Steps Description y = 1– 2sin²2x Original function Apply the double angle identity y = 2 cos (2 · 2x) cos 2A = 1– 2sin²A to rewrite the function 2 cos 4x Note: In place of A we have 2x in our original V = | function The original function y = 1 – 2sin²2xis rewritten as y = 2 cos 4x.
Textbook Problem Graph each of the following from x = 0 to x = 2x. y = 1- 2sin 2x The answer in the back of the book says the answer is y=cos4x which is what I got too. But bartleby says it's: Concept Involved: We need to rewrite the given function using the double angle identity, and then graph it in the given interval. Calculation: Steps Description y = 1– 2sin²2x Original function Apply the double angle identity y = 2 cos (2 · 2x) cos 2A = 1– 2sin²A to rewrite the function 2 cos 4x Note: In place of A we have 2x in our original V = | function The original function y = 1 – 2sin²2xis rewritten as y = 2 cos 4x.
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Hello, please see the attached picture, which is correct?
Transcribed Image Text:Chapter 5.3, Problem 27PS
Textbook Problem
Graph each of the following from x = 0 to x = 27.
y = 1– 2sin 2x
The answer in the back of the book says the answer is y=cos4x,
which is what I got too. But bartleby says it's:
Concept Involved:
We need to rewrite the given function using the double angle
identity, and then graph it in the given interval.
Calculation:
Steps
Description
y = 1– 2sin²2x
Original function
Apply the double angle identity
cos 2A = 1– 2sin²A to rewrite the function
Note: In place of A we have 2x in our original
function
y = 2 cos (2 - 2r).
2 cos 4x
V=
The original function y = 1– 2sin²2x is rewritten as y
2 cos 4x
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