What is the cardinality of Property_Service to GG_Service: textTimes...1I112 +BIUA23O+45PROPERTY_SERVICE must exist in SERVICEGG SERVICE to PROPERTY SERVICE: This relationship indicates that everyProperty Service should match a service listed in the company's GG SERVICE table. A singleservice can link to numerous property services, yet each property service is dedicated to a singleservice type, the relationship's cardinality is one-to-many. The GG SERVICE table presumablycatalogs the various services Garden Glory offers, and each entry in the Property Service mustbe tied to one of these service types, establishing a one-to-many relationship betweenProperty Service and Service.PROPERTY SERVICE to GG SERVICE:PROPERTY SERVICE must exist in EMPLOYEEThe relationship from EMPLOYEE to PROPERTY_SERVICE is many-mandatory. This isbecause the same employee can perform multiple property services, and it is mandatory that the QUESTIONSAssume that Garden Glory designs a database with the following tables:OWNER (OwnerID, OwnerName, OwnerEmailAddress, Owner Type)OWNED PROPERTY (PropertyID, PropertyName, Property Type, Street, City,State, Zip, OwnerID)GG SERVICE (ServiceID, ServiceDescription, Cost PerHour);EMPLOYEE (EmployeeID, LastName, FirstName, CellPhone, ExperienceLevel)PROPERTY SERVICE (PropertyServiceID, PropertyID, ServiceID, ServiceDate,EmployeeID, Hours Worked)The referential integrity constraints are:OwnerID in OWNED PROPERTY must exist in OwnerID in OWNERPropertyID in PROPERTY SERVICE must exist in PropertyID in OWNED_PROPERTYServiceID in PROPERTY_SERVICE must exist in ServiceID in GG_SERVICEEmployeeID in PROPERTY_SERVICE must exist in EmployeeID in EMPLOYEEAssume that OwnerID in OWNER, PropertyID in PROPERTY, ServiceID in GG_SER-VICE, EmployeeID in EMPLOYEE, and PropertyServiceID in PROPERTY_SERVICEare surrogate keys with values as follows:OwnerIDStart at 1Increment by 1PropertyIDStart at 1Increment by 1ServiceIDStart at 1Increment by 1EmployeeIDStart at 1Increment by 1PropertyServiceIDStart at 1Increment by 1

It seems you’re describing a database schema for a service company like Garden Glory. Here’s a…

text 4 Times... 1 12 + B I U A © 2 3 + 4 5 t = ▾ PROPERTY SERVICE must exist in SERVICE GG SERVICE to PROPERTY SERVICE: This relationship indicates that every Property Service should match a service listed in the company's GG SERVICE table. A single service can link to numerous property services, yet each property service is dedicated to a single service type, the relationship's cardinality is one-to-many. The GG SERVICE table presumably catalogs the various services Garden Glory offers, and each entry in the Property Service must be tied to one of these service types, establishing a one-to-many relationship between Property Service and Service. PROPERTY SERVICE to GG SERVICE: PROPERTY SERVICE must exist in EMPLOYEE

text 4 Times... 1 12 + B I U A © 2 3 + 4 5 t = ▾ PROPERTY SERVICE must exist in SERVICE GG SERVICE to PROPERTY SERVICE: This relationship indicates that every Property Service should match a service listed in the company's GG SERVICE table. A single service can link to numerous property services, yet each property service is dedicated to a single service type, the relationship's cardinality is one-to-many. The GG SERVICE table presumably catalogs the various services Garden Glory offers, and each entry in the Property Service must be tied to one of these service types, establishing a one-to-many relationship between Property Service and Service. PROPERTY SERVICE to GG SERVICE: PROPERTY SERVICE must exist in EMPLOYEE

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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