Tetwo-uagiee ur iCCaonIT Compelsauor with sUL pomt wCigntng Is. r() y(t) sp [6.4.1] d sd
Tetwo-uagiee ur iCCaonIT Compelsauor with sUL pomt wCigntng Is. r() y(t) sp [6.4.1] d sd
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
- Consider PD-Control with set-point weighting by setting ki = 0 in Equation 6.4.1. Determine the closed-loop transfer function from the position reference, r, to the angular position output, θ in radians, i.e., Y(s)/R(s), in terms of K, τ, bsp, kp and kd/ then, Determine kp and kd in terms of the closed-loop natural frequency, ωn, damping ratio, ζ, motor time constant, τ, and motor gain constant, K.
![Tetwo-uagiee ur iCCaonIT
Compelsauor with sUL pomt wCigntng Is.
r()
y(t)
sp
[6.4.1]
d
sd](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12c18db6-f6e8-4129-b933-2f1b3972f7de%2F7cb640ac-93a8-4fec-a989-04b0cd138cf1%2Fpjv44wu.png&w=3840&q=75)
Transcribed Image Text:Tetwo-uagiee ur iCCaonIT
Compelsauor with sUL pomt wCigntng Is.
r()
y(t)
sp
[6.4.1]
d
sd
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Part 1:
Write the expression for the two-degree of freedom PID compensator with set point weighting and Substitute 0 for ki,
![d
dt
dt
d
u(t)k, (bgr(t)-y(1)) + k b
dt
dt](https://content.bartleby.com/qna-images/answer/12c18db6-f6e8-4129-b933-2f1b3972f7de/b5d060cb-ff50-4767-8a15-0d67f06315c0/y4qwnko.png)
Step 2
Take the Laplace transform,
![U(s) ,(bR(s)-Y(s)) + k,s(bR(s) -Y (s)
U(s)=(k,bg kb)R(s) - (k, -k,s)Y(s)
.(1)](https://content.bartleby.com/qna-images/answer/12c18db6-f6e8-4129-b933-2f1b3972f7de/b5d060cb-ff50-4767-8a15-0d67f06315c0/54eh5ak.png)
Step 3
Write the expression for transfer function for the motor,
![Y (s)
U (s)
1
m
R
Ja
Rm
Y(s)
U (s)
1
eq*m s+1
k s
m
(
J R
-s +1 Y(s)
.(2)
U (s) ks
X](https://content.bartleby.com/qna-images/answer/12c18db6-f6e8-4129-b933-2f1b3972f7de/b5d060cb-ff50-4767-8a15-0d67f06315c0/43m9bq.png)
Step 4
Equate the equation (1) and equation (2),
![JR
eq
-s 1
(k,bg +kb)R(s)-(k, -k,s)Y(s) =k_|
k2
(JR
(k,bg +kbsR(s)=k|
"s+1+k, -ks Y (s)
eqm
(k,bg + k,b)
Y(s)
R(s)
J R
eq
- ki s+1+k
k2](https://content.bartleby.com/qna-images/answer/12c18db6-f6e8-4129-b933-2f1b3972f7de/b5d060cb-ff50-4767-8a15-0d67f06315c0/08viiv.png)
Step 5
This expression is the open loop transfer function. Here, there is a negative unity feedback system.
Thus,
![(kb +kbs)
G(s)
J R
eq
- k s1k
k2
m](https://content.bartleby.com/qna-images/answer/12c18db6-f6e8-4129-b933-2f1b3972f7de/b5d060cb-ff50-4767-8a15-0d67f06315c0/i24dzev.png)
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