Testing the silver content of coin 4 and coin 1. Now if it switches the two-sample t-test around it gives us the result of B. Justify your conclusion in terms of the derivative of the parameter transformation involved.
Testing the silver content of coin 4 and coin 1. Now if it switches the two-sample t-test around it gives us the result of B. Justify your conclusion in terms of the derivative of the parameter transformation involved.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![А,
B,
Two-Sample T-Test and Cl: Coin4, Coin1
E COINS (2)MWx
Two-Sample T-Test and Cl: Coin4, Coin1
Method
Method
: mean of Coind
Pa mean of Coin1
Difference: -a
u mean of Coin4
a mean of Coint
Difference: - Pa
Equal voriances are assumed for this analysis
Equal variances ore assumed for this analysis.
Descriptive Statistics
Sample
Descriptive Statistics
Coind
Coint
N Mean StDev SE Mean
5614
6.744
0.363
0543
0.14
0.18
Sample
N Mean StDev SE Mean
Coind
5.614
0.363
0.14
Coin1
9 6.744 0.543
018
Estimation for Difference
Estimation for Difference
90% CI for
Pooled
StDev
0.474 (-1.551-0.709)
Difference
Difference
90% CI for
Pooled
StDev
0.474 -1551,-0.709)
-1.130
Difference
1.130
Difference
Test
Test
Null hypothesis
Alternative hypothesis H,: H - Pz # 0
T-Value DF p-Value
Null hypothesis
He - Ha 0
Alternative hypothesis H u - Hz # 0
T-Value DF P-Value
14
-473
14
0.000
-473
0.000
Question:
Testing the silver content of coin 4 and coin 1. Now if it switches the two-sample t-test around it
gives us the result of B. Justify your conclusion in terms of the derivative of the parameter
transformation involved.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc0557e0e-7c52-43d2-b9f4-a887bc43498a%2Ff714c810-c644-4d6c-b42f-fb559d329324%2Fsuwn005_processed.jpeg&w=3840&q=75)
Transcribed Image Text:А,
B,
Two-Sample T-Test and Cl: Coin4, Coin1
E COINS (2)MWx
Two-Sample T-Test and Cl: Coin4, Coin1
Method
Method
: mean of Coind
Pa mean of Coin1
Difference: -a
u mean of Coin4
a mean of Coint
Difference: - Pa
Equal voriances are assumed for this analysis
Equal variances ore assumed for this analysis.
Descriptive Statistics
Sample
Descriptive Statistics
Coind
Coint
N Mean StDev SE Mean
5614
6.744
0.363
0543
0.14
0.18
Sample
N Mean StDev SE Mean
Coind
5.614
0.363
0.14
Coin1
9 6.744 0.543
018
Estimation for Difference
Estimation for Difference
90% CI for
Pooled
StDev
0.474 (-1.551-0.709)
Difference
Difference
90% CI for
Pooled
StDev
0.474 -1551,-0.709)
-1.130
Difference
1.130
Difference
Test
Test
Null hypothesis
Alternative hypothesis H,: H - Pz # 0
T-Value DF p-Value
Null hypothesis
He - Ha 0
Alternative hypothesis H u - Hz # 0
T-Value DF P-Value
14
-473
14
0.000
-473
0.000
Question:
Testing the silver content of coin 4 and coin 1. Now if it switches the two-sample t-test around it
gives us the result of B. Justify your conclusion in terms of the derivative of the parameter
transformation involved.
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