Testing a claim about a Population Mean, " Assume a normal distribution and use an 0.05 significance level. Sample data yielded the following summary results from a study of body temperatures of 12 healthy adults: x-98.39 s-0.535 Test the claim that normal body temperature is less than 98.6°. 1. Claim in symbols alternative hypotheses 2. Null and H,: H,: 3. Туре of tail 4. Critical value(s) 5. Decision Curve 6. Test statistic 7. Conclusion about the null hypothesis 8. Conclusion in words that address the original claim

Testing a claim about a Population Mean, " Assume a normal distribution and use an 0.05 significance level. Sample data yielded the following summary results from a study of body temperatures of 12 healthy adults: x-98.39 s-0.535 Test the claim that normal body temperature is less than 98.6°. 1. Claim in symbols alternative hypotheses 2. Null and H,: H,: 3. Туре of tail 4. Critical value(s) 5. Decision Curve 6. Test statistic 7. Conclusion about the null hypothesis 8. Conclusion in words that address the original claim

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Description: Testing a claim about a Population Mean, "Assume a normal distribution and use an 0.05significance level. Sample data yielded the followingsummary results from a study of body temperaturesof 12 healthy adults: x=98.39 s= 0.535Test the claim that nor

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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2. Hypothesis: A one hour GRE workshop increases test scores. Sample Data: Mean of 25 people who did workshop = 156 (standard deviation = 8.2); mean of 27 people who did not do workshop = 154 (standard deviation 7.6).
Using a 1-7ikert scale, a researcher measured respondents desirability towards cars, and he hypothesized that the respondents rated 4 out of 7 in their desirability towards 2 seat runabout sport electric vehicle. Referring to the SPSS output which of the foliowing statements /are correct? One-Sample Statistics Mean Std. Deviation Std. Error Mean Desirability: 2 Seat Runabout Sport Electric 1000 3.92 1.537 .049 One-Sample Test Test Value 4 95% Confidence Interval of the Mean Difference Sig (2-tailed) Difference Lower Upper Desirability: 2 Seat Runabout Sport Electric -1.626 999 .104 -.079 17 02 The researcher's alternate hypothesis is supported O b All answers are correct Oc The researcher's test value is higher than the average score rated by respondents. O d. The test value falls within the 95% confidence interval of the dataset.
The weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces.Refer to Exhibit 6-5. What is the random variable in this experiment? a. 8 ounces b. Weight of items produced by a machine c. Normal distribution d. 2 ounces
The mean number of eggs per person eaten in the United States is 223. Do college students eat a different number of eggs than the average American? The 51 college students surveyed averaged 237 eggs per person and their standard deviation was 39.3. What can be concluded at the a = 0.01 level of significance? %3D a. For this study, we should use Select an answer b. The null and altemative hypotheses would be: H 2 Select an answer v H 2vSelect an answer v c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is | ? v a f. Based on this, we should Select an answer V the null hypothesis. g. Thus, the final conclusion is that... O The data suggest that the populaton mean is significantly different from 223 at a = 0.01, so there is statistically significant evidence to conclude that the population mean number of eggs consumed by college students per year is different from 223. Toctor O The data…
A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p=0.5H1: p≠0.5B.H0: p=0.5H1: p>0.5C.H0: p=0.5H1: p<0.5D.H0: p≠0.5H1: p=0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? χ2 Normal distribution Student (t) distribution
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A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 78 girls in 144 births, so the sample statistic of 1324 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed Right-tailed Two-tailedPart 5e. What is the value of the test statistic?The test statistic is enter your response here. (Type an integer or a decimal.)Part 6f. What is the P-value?The P-value is enter your response here. (Round to four decimal places as needed.)
Find Test Statistic, P value, and Z score.
A newspaper article noted that the mean life span for 35 male symphony conductors was 73.2 years with a standard deviation of 8.7 . Males in the general population have a mean life span of 69.5 years. Use a 0.05 significance level to test the claim that male symphony conductors have a mean life span that is greater than 69.5 years. a. Define the parameter A. mu = The mean life span of the 35 male symphony conductors in the sample B. p = The proportion of all male symphony conductors who life more than 69.5 years C. mu = The mean life span of all male symphony conductors D. mu = The mean life span of all males b. State the null and alternative hypotheses A. Upper H 0 : mu equals 73.2 Upper H 1 : mu greater than 73.2 B. Upper H 0 : mu equals 69.5 Upper H 1 : mu greater than 69.5 C. Upper H 0 : mu greater than 69.5 Upper H 1 : mu equals 69.5 D. Upper H 0…