Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Testing a asking question.
![1) mass of benzil = moles x molar mass of benzil
= 0.35 mmol x 210.232 g/mol
= 73.5812 x 10^-3 g
= 73.58 mg
mass of benzoin=0.35 mmol x 212.24 g/mol
= 74.284 x 10^-3 g
= 74.284 mg
2)
a) one mole of sodium borohydride (NABH4) can reduce four moles of aldehyde or
ketone
therefore
one mole of sodium borohydride (NaBH4) can reduce 2 moles of benzil because benzil
has 2 ketone group
and
for 0.35 mmol of benzil , moles of NABH4 required = 0.35 mmol / 2 = 0.175 mmol
thus
mass of NaBH4 = 0.175 mmol x 37.83 g/mol
= 6.62 mg
b) as we know that for 0.35 mmol of benzil , only 6.62 mg of NaBH4 is required
therefore
15 mg is very large and Only 0.35 mmol of benzil , leads to the result that
benzil is the limiting reagent.
3) the balanced reaction or the reaction of the NaBH4 with H2O is given as
NABH4 + 3 H20
NaH2BO3 + 4 H2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5204889d-2bad-42ec-8fd6-b7c2e67aa91d%2Fc7958c6d-4cb4-4079-a08d-fe1d73a69816%2F0v7pkri_processed.gif&w=3840&q=75)
Transcribed Image Text:1) mass of benzil = moles x molar mass of benzil
= 0.35 mmol x 210.232 g/mol
= 73.5812 x 10^-3 g
= 73.58 mg
mass of benzoin=0.35 mmol x 212.24 g/mol
= 74.284 x 10^-3 g
= 74.284 mg
2)
a) one mole of sodium borohydride (NABH4) can reduce four moles of aldehyde or
ketone
therefore
one mole of sodium borohydride (NaBH4) can reduce 2 moles of benzil because benzil
has 2 ketone group
and
for 0.35 mmol of benzil , moles of NABH4 required = 0.35 mmol / 2 = 0.175 mmol
thus
mass of NaBH4 = 0.175 mmol x 37.83 g/mol
= 6.62 mg
b) as we know that for 0.35 mmol of benzil , only 6.62 mg of NaBH4 is required
therefore
15 mg is very large and Only 0.35 mmol of benzil , leads to the result that
benzil is the limiting reagent.
3) the balanced reaction or the reaction of the NaBH4 with H2O is given as
NABH4 + 3 H20
NaH2BO3 + 4 H2
![A
ABC is triangle with D and E the midpoints of
AB and AC respectively.
E
Prove that BC=2DE.
В
C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5204889d-2bad-42ec-8fd6-b7c2e67aa91d%2Fc7958c6d-4cb4-4079-a08d-fe1d73a69816%2Feqovbvh_processed.png&w=3840&q=75)
Transcribed Image Text:A
ABC is triangle with D and E the midpoints of
AB and AC respectively.
E
Prove that BC=2DE.
В
C
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