Test your might! 1) Given the charge distribution below -10 nC 5 nC + 2 cm 1 cm +) 10 nC A a) Determine the magnitude and the direction of the electric field at point A. b) What is the direction and magnitude of the force on a proton?
Q: 1. The charge Q1 = 5mC lies at A(- 4; 6) m , Q2 = - 5mC lies at B(6; 2) m, Q3 = 10 mC lies at C(4;…
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Q: Three point charges are aligned along the x axis as shown in the figure below. -0.500 m- -0.800 m- x…
A: Step 1: Step 2: Step 3: Step 4:Step 5:
Q: Three electric charges are placed along the x-axis as follows : a +16 nC charge is placed at x =…
A: q1= +16 nC at x = -8 cm, q2 = -20 nC at x = +4 cm, q3 = -10 nC at x = +10 cm.
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Hello Please answer question #2 using the charge of a proton as 1.6 x 10^{-19}. Thank you.
![1EST NUR HIGHI
Test your might!
1) Given the charge distribution below
-10 nC
5 nC
+
2 cm
1 cm
+)
10 nC
A
a) Determine the magnitude and the direction of the electric field at
point A.
b) What is the direction and magnitude of the force on a proton?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fafa4cb6f-0c50-4ba8-9a03-e3918106ad13%2F5f6466b1-ef51-4340-afab-b49f3a4fd5d3%2Fezdeweu_processed.png&w=3840&q=75)
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- Charge q, = 2.50 nC is at x, = 0 and charge q, = 6.00 nC is at x, = 4.00 m. At what point between the two charges is the electric field equal to zero? (Enter the x coordinate in m.) HINT Write an expression for the net electric field as a function of position, x, in the region between the two charges. (Don't forget that the electric field is a vector, so direction is important!) Set this expression equal to zero and solve for the variable x using the quadratic equation. Click the hint button again to remove this hint. mCoulomb’s law for the following problem use k = 9 x 10^9 N.m^2/C^2An average human weighs about 700 N .If two such generic humans each carried 3.0 C coulomb of excess charge, one positive and one negative, how far apart would they have to be for the electric attraction between them to equal their 700 N weight? So first I AM BLIND! YOUR IMAGES/EQUATION EDITOR CAN'T BE READ BY MY SCREEN READER!! SO FOR HELP PLEASE JUST WRITE IT OUT IN HTML TEXT (THE LITERL CHARACTERS YOU ARE READING RIGHT NOW) PLEASE!! So I know f=1/(4pi*epsilon)*abs(q1*q2))/r^(2) and we are looking for R here. o first epsilon = 9.8*10^(9) and with all of that information you need to manipulate to solve for R. I get r= sqrt(1/4*pi()*epilison)*abs(q1*q2). From there I am getting a wrong answer and can't figure out what is going on with thealgebra. So could someone help me figur out what needs to be done to the initial equation to solve for r? and finally again please no graphs, images, or anything and just can read the html text. appreciate the help if someone is willing to…
- A pair of unlike charges equal in magnitude and separated by a small distance is known as a dipole. Such a pair is situated on the x axis at equal distances from the origin as shown in the figure below. Use the direction rosette to answer the questions. ΧΑ 8 + * D E B 3 +q -9 5 9 zero magnitude (a) What is the direction of the net electric field at location C due to both charges? 5 X Did you consider the symmetry of the situation? What is the net contribution to the field from the y components of the field from each charge? (b) What is the direction of the net electric field at location D due to both charges? ---Select--- v (c) What is the direction of the net electric field at location E due to both charges? ---Select--- ✓ Additional Materials Reading 7Consider an object of mass 41.8 kg. Now imagine taking all the protons out of the object and stuffing them into a box. Also take all the electrons out of the object and stuff them in a second box. How much charge is contained in the box with all the protons? 8.00E+09 C 1.00E+09 C 2.00E+09 C 4.00E+09 C5. Two parallel, metal plates with separation distance d=2.00 cm carry charges of equal magnitude but opposite sign. Assume the electric field has a magnitude of 2,000 N/C. A charged particle with mass 2.00x10-16 kg and charge 1.00x106 C is projected from the center of the bottom negative plate with an initial speed of 1.00x105 m/s at an angle of 45 degrees above the horizontal. Assume the plates are square with side length 20.0 cm. a. Where does the particle strike? Answer: b. What is the minimum initial speed the particle must have in order to reach the positive plate. Answer:
- 11:05 < Back E_M_HW-2.pdf Dashboard +q 000 000 Calendar a 3 Pra 4) Four charges are an equal distance r from some origin. What is the direction of the electric field, E, at the origin, due to the four charges? Then what is the magnitude of E at the origin. Charge values are given in the picture. 12 国 To Do Q ام B Notifications InboxPlease explain9:09 docs.google.com 4. Applying Conservation of Charge: A researcher is analyzing a particle decay process. The data for one experiment shows a particle of charge -3e, decaying to form two new particles. One of the new particles has a charge of - e. -3e Choose -1 e +3 e n -2 e +2 e e with the correct words in the following Conservation of Charge Review: a) Charge is neither created nor destroyed, it can only be (siphoned/ transferred added) from one 10 points Q? -e * 25 points