Test whether there is a difference in the 5 types of cement mortar at a significance level of 0.05. Concrete test results as table below :
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A study wants to test the hypothesis that there are differences regarding the effect of five types of concrete mix on the absorption of water vapor.
Furthermore, suppose that all 30 experimental boxes are available.
Test whether there is a difference in the 5 types of cement mortar at a significance level of 0.05.
Concrete test results as table below :
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- Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x=101.22, y=102.45, r=0.916, P-value=0.000, and y=−8.44+1.1x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 99? Use a significance level of 0.05.Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.16, y = 102.3, r= 0.810, P-value = 0.000, and y = 23.09+0.78x, where x represents the IQ score of the wife. Find the best %3D %3D %3D predicted value of y given that the wife has an IQ of 109? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. .... The best predicted value of y is . (Round to two decimal places as needed.) Critical values of the pearson correlation coefficient r NOTE: To test Ho: p = 0 against H,: p#0, reject Ho |if the absolute value of r is greater than the critical value in the table. a = 0.05 a = 0.01 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40…A dietician wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Six randomly selected subjects were pretested, and then they took the mineral supplement of a 6 week period. The results are shown in the table below. Can it be concluded that the cholesterol level has changed at a significance level of 0.10? Use the P-value method with your calculator. Assume the variable is approximately normally distributed. You can use your calculator to answer this question but make sure that you clearly write the statements for the null and alternative hypothesis. Be sure that you thoroughly explain your final conclusion using the P-value method. Subject 1 2 3 4 5 6 Before 210 235 208 190 172 244 After 190 170 210 188 173 228
- A scientist wants to examine factors that may be related to cancer. The scientist believes that differences in age at death that will be found when determining what type of smoker a person was (pipe smoker, cigar smoker, cigarette smoker, or nonsmoker) but he also thinks it is important to consider the extent of smog in the person’s environment. For this new extended study, the people in the sample are divided up into those who lived in areas with heavy smog and those who lived in areas that were relatively free from smog. Smoking habit remains the other independent variable, and the dependent variable remains age at death. The new question of major interest to the scientist is whether the pattern of differences in age at death attributed to smoking habits would be influenced by whether people lived in smog-filled environments. What is the appropriate statistic? a. Dependent groups t-test b. Phi Coefficient c. Point Biserial r d. t-test for r > 0…Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 99.37, y = 98.55, r=0.859, P-value = 0.000, and y = 10.94 +0.88x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 105? Use a significance level of 0.05. 10CritPearson.pdf O A. 98.55 OB. 0.88 O C. 99.37 O D. 103.34A researcher wanted to test whether there is a relationship between preferred sweet (Oreo cookies, Mars bars, or Twinkies) and age group (children, adolescents, or young adults). To test that, subjects from the three age groups were asked which of the three sweets they preferred. Which statistical test should be used to analyze the data? 1. chi square test of independece 2. chi square test for goodness of fit 3. one sample t test 4. one way anova test
- A dietitian wishes to see if a person's cholesterol level will change if the diet is supplemented by a certain mineral. Seven subjects were pretested and then took the mineral supplement for a six-week period. The results are shown below in the table. Use a paired samples t-chart at a = 0.01 significance level to see difference (Before - After) between the cholesterol levels. State the hypotheses and conclusion. Also, conduct a 99% confidence interval. Subject 1 Before 210 After 190 2 205 170 3 208 210 4 192 188 5 178 173 6 244 228 7 211 198Samples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site. Pond 1: 37.03, 37.45, 36.75, 37.54, 37.71, 37.02, 37.32 Pond 2: 38.89, 39.05, 38.51, 38.53, 38.71 Use a 2% significance level to test the claim that the two ponds have the same mean salinity value. Assume that nothing is known about the population distribution of salinities. (a) Enter the rank values in the same order as in the original sample. The rank values for Pond 1 are: The rank values for Pond 2 are: (b) The test statistic is: . (c) The test critical value is: . (d) The conclusion isA. There is not sufficient evidence to indicate that the two ponds have different distributions of salinity values.B. There is sufficient evidence to indicate that the two ponds have different distributions of salinity values.As an occupational health epidemiologist you are required to measure the effect of stress on the workers in your manufacturing plant. Two different tests previously developed to measure stress in industrial workers are selected: stress test alpha and stress test delta. The sensitivity and specificity of each test are shown below. Which test generates the greatest proportion of false negatives? Stress Test Alpha Stress Test Delta Sensitivity = 60% 75% M Specificity = 95% 90% Stress Test Alpha Stress Test Delta
- n 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 25 30 35 40 45 50 60 70 80 90 100 n x=0.05 0.950 0.878 0.811 0.754 0.707 0.666 0.632 0.602 0.576 0.553 0.532 0.514 0.497 0.482 0.468 0.456 0.444 0.396 0.361 0.335 0.312 0.294 0.279 0.254 0.236 0.220 0.207 0.196 α = 0.05 α = 0.01 0.990 0.959 0.917 0.875 0.834 0.798 0.765 0.735 0.708 0.684 0.661 0.641 0.623 0.606 0.590 0.575 0.561 0.505 0.463 0.430 0.402 0.378 0.361 0.330 0.305 0.286 0.269 0.256 α = 0.01 NOTE: To test Ho: p=0 against H₁: p0, reject Ho if the absolute value of ris greater than the critical value in the table.Select all that apply: We should reject H0. We should not reject H0. At the 1% significance level, the data do not provide sufficient evidence to conclude that the amount of time American teenagers watch television per week is different from 14.1 hours. At the 1% significance level, the data provide sufficient evidence to conclude that the amount of time American teenagers watch television per week is different from 14.1 hours.Listed below are the number of cricket chirps in 1 min and the corresponding temperatures in degrees Fahrenheit. Is there sufficient evidence to conclude that there is a relationship between the number of cricket chirps in 1 min and the temperature? Use a significance level of α=0.05. Chirps in 1 min 1171 1105 1185 852 1089 950 917 862 Temperature (°F) 78.4 88.2 91.5 86.3 90.2 79.3 83.8 84.4 Determine the null and alternative hypotheses for this test. Find the value of the correlation coefficient. rs=enter your response here (Round to three decimal places as needed.) Determine the critical value(s) of the correlation coefficient. enter your response here (Round to three decimal places as needed. Use a comma to separate answers as needed.)