)Test using the p-value approach with a- 0.05. State the nul and alternative hypothesis. O MoH0.6 versus .4 O Moi H« 98.6 versus H 98.6 O Mo H.6 versus .4 O Mo H.6 versus H .6 O Mg! - 98.6 versus H> 8.4 Find the test statistic and the prvalue. (Round your tast statistic to tve decimal places and your prvalue to four decimal places.) p-value State your conclusion. O The prvalue is greater than alpha se Mg la not rejected. There is insufficient evidence to indicate that the average bedy temperature for healthy humans deviates from 98.6. O The p-value is less than alpha so Hg ia regected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The prvalue is less than alpha so Mg is rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6. O The prvalue is greater than alpha se Hg ia not rejected. There is sufficent evidence to indicate that the average body temperature for healthy humans deviates from 98.6. ) Test using the crtical value appreach with a 0.05. Find the rejection regien. (Round yaur ansrers to bvo decimal places. 4 the test is ene-taled. enter NONE for the unused region,) State yeur conclusion. O The test statistic does not lie in the rejection region so He is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6. O The test statistie lies in the rejection region se Hg la rejected. There is sufficient evidence te indicate that the average body temperature for healthy humans deviates from 98.6. O The test statistic lies in the rejection region so Hg a rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 96.6. O The test statistic does not lie in the rejection region so Hg is not rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6. 0 Compare the cencelusiens from parts (a) and (b). Are they the same?

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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this question has parts a, b, c, and d

What is normal, when it comes to people's body temperatures? A random sample of 130 human body temperatures had a mean of 98.15° and a standard deviation of 0.74°. Does the data indicate that the average body temperature for healthy humans deviates from 98.6°, the usual average temperature cited by physicians and others?
(a) Test using the p-value approach with a = 0.05.
State the null and alternative hypothesis.
O Ho: u = 98.6 versus H:H < 98.6
O Ho: l < 98.6 versus H: H > 98.6
O Ho: H + 98.6 versus H: u = 98.6
O Ho: u = 98.6 versus H: u # 98.6
O Hoi u = 98.6 versus H:u > 98.6
Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)
p-value =
State your conclusion.
O The p-value is greater than alpha so H, is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
O The p-value is less than alpha so H, is rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
O The p-value is less than alpha so H, is rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
O The p-value is greater than alpha so Ho is not rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
(b) Test using the critical value approach with a = 0.05.
Find the rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.)
State your conclusion.
O The test statistic does not lie in the rejection region so H, is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
O The test statistic lies in the rejection region so H, is rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
O The test statistic lies in the rejection region so Hn is rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
O The test statistic does not lie in the rejection region so H, is not rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.
(c) Compare the conclusions from parts (a) and (b). Are they the same?
O Yes, both methods produce the same conclusion.
O No, the p-value approach rejects the null hypothesis when the critical approach fails to reject the null hypothesis.
O No, the critical value approach rejects the null hypothesis when the p-value approach fails to reject the null hypothesis.
(d) The 98.6° standard was derived by a German doctor in 1868, who claimed to have recorded 1 million temperatures in the course of his research.t What conclusions can you draw about his research in light of your conclusions in parts (a) and (b)?
O It appears as though the doctor was correct in his conclusion.
O It appears as though the the doctor's equipment may not have been accurate.
Transcribed Image Text:What is normal, when it comes to people's body temperatures? A random sample of 130 human body temperatures had a mean of 98.15° and a standard deviation of 0.74°. Does the data indicate that the average body temperature for healthy humans deviates from 98.6°, the usual average temperature cited by physicians and others? (a) Test using the p-value approach with a = 0.05. State the null and alternative hypothesis. O Ho: u = 98.6 versus H:H < 98.6 O Ho: l < 98.6 versus H: H > 98.6 O Ho: H + 98.6 versus H: u = 98.6 O Ho: u = 98.6 versus H: u # 98.6 O Hoi u = 98.6 versus H:u > 98.6 Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.) p-value = State your conclusion. O The p-value is greater than alpha so H, is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The p-value is less than alpha so H, is rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The p-value is less than alpha so H, is rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The p-value is greater than alpha so Ho is not rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. (b) Test using the critical value approach with a = 0.05. Find the rejection region. (Round your answers to two decimal places. If the test is one-tailed, enter NONE for the unused region.) State your conclusion. O The test statistic does not lie in the rejection region so H, is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The test statistic lies in the rejection region so H, is rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The test statistic lies in the rejection region so Hn is rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. O The test statistic does not lie in the rejection region so H, is not rejected. There is sufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°. (c) Compare the conclusions from parts (a) and (b). Are they the same? O Yes, both methods produce the same conclusion. O No, the p-value approach rejects the null hypothesis when the critical approach fails to reject the null hypothesis. O No, the critical value approach rejects the null hypothesis when the p-value approach fails to reject the null hypothesis. (d) The 98.6° standard was derived by a German doctor in 1868, who claimed to have recorded 1 million temperatures in the course of his research.t What conclusions can you draw about his research in light of your conclusions in parts (a) and (b)? O It appears as though the doctor was correct in his conclusion. O It appears as though the the doctor's equipment may not have been accurate.
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