Test tube 1 contain hexane, test tube 2 contains fluorene, test tube 3 contains Fluorenone On the column chromatography, dot A represent hexane, dot B represent fluorene and dot C represent fluorenone. A = 4.5 mm B = 2.5 mm C = 5.3 mm Rf = A/C = 4.5/5.3 = 0.85 mm Rf = B/C = 2.5/5.3 = 0.47 mm
Test tube 1 contain hexane, test tube 2 contains fluorene, test tube 3 contains Fluorenone On the column chromatography, dot A represent hexane, dot B represent fluorene and dot C represent fluorenone. A = 4.5 mm B = 2.5 mm C = 5.3 mm Rf = A/C = 4.5/5.3 = 0.85 mm Rf = B/C = 2.5/5.3 = 0.47 mm
Macroscale and Microscale Organic Experiments
7th Edition
ISBN:9781305577190
Author:Kenneth L. Williamson, Katherine M. Masters
Publisher:Kenneth L. Williamson, Katherine M. Masters
Chapter9: Column Chromatography: Fluorenone, Cholesteryl Acetate, Acetylferrocene, And Plant Pigments
Section: Chapter Questions
Problem 5Q
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do both
![Test tube 1 contain hexane, test tube 2 contains fluorene, test tube 3 contains
fluorenone
On the column chromatography, dot A represent hexane, dot B represent fluorene
and dot C represent fluorenone.
A = 4.5 mm
B = 2.5 mm
C = 5.3 mm
Rf = A/C = 4.5/5.3 = 0.85 mm
Rf = B/C = 2.5/5.3 = 0.47 mm
1. Based on Rf values of two compounds you separated from the column, explain
which column is more polar and why the polar compound moves slower in the
column.
2. Hexane was used to elute fluorene from the column, but 70% hexane-30%
acetone was required to elute fluorenone. Why was 70% hexane - 30% acetone
required to elute fluorenone from the column?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf922873-5540-4481-ab4e-e86a6105bdb6%2F3ac288e0-67cc-44cb-bddb-d8f62121c7e5%2Fjlrft2c_processed.png&w=3840&q=75)
Transcribed Image Text:Test tube 1 contain hexane, test tube 2 contains fluorene, test tube 3 contains
fluorenone
On the column chromatography, dot A represent hexane, dot B represent fluorene
and dot C represent fluorenone.
A = 4.5 mm
B = 2.5 mm
C = 5.3 mm
Rf = A/C = 4.5/5.3 = 0.85 mm
Rf = B/C = 2.5/5.3 = 0.47 mm
1. Based on Rf values of two compounds you separated from the column, explain
which column is more polar and why the polar compound moves slower in the
column.
2. Hexane was used to elute fluorene from the column, but 70% hexane-30%
acetone was required to elute fluorenone. Why was 70% hexane - 30% acetone
required to elute fluorenone from the column?
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