Test the pair of events E and D for independence based on the following table. Events A, B, and C are mutually exclusive. Events D and E are mutually exclusive. D E Totals A 0.20 0.30 0.50 B 0.12 0.18 0.30 C 0.08 0.12 0.20 Totals 0.40 0.60 1.00 Are the events E and D independent? Select the correct answer below and fill in the answer boxes to complete your choice. O A. No, they are not independent because P(END) #P(E)P(D). P(End) = OB. Yes, they are independent because P(END) #P(E)P(D). P(END)= OC. Yes, they are independent because P(END)=P(E)P(D). P(END)= OD. No, they are not independent P(END)=P(E)P(D). P(END) = and P(E)P(D)= and P(E)P(D)= and P(E)P(D)= and P(E)P(D)=

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Chapter2: Second-order Linear Odes
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Test the pair of events E and D for independence based on the following table. Events A, B, and C are mutually
exclusive. Events D and E are mutually exclusive.
D
E
Totals
A
0.20
0.30
0.50
B
0.12
0.18
0.30
с
0.08
0.12
0.20
Totals
0.40
0.60
1.00
and P(E)P(D)=
Are the events E and D independent? Select the correct answer below and fill in the answer boxes to complete your
choice.
and P(E)P(D)=
O A. No, they are not independent because P(END)*P(E)P(D). P(End) =
OB. Yes, they are independent because P(END) #P(E)P(D). P(END)=
OC. Yes, they are independent because P(END)=P(E)P(D). P(END)=
OD. No, they are not independent P(END) = P(E)P(D). P(END)= and P(E)P(D)=
and P(E)P(D)=
Transcribed Image Text:Test the pair of events E and D for independence based on the following table. Events A, B, and C are mutually exclusive. Events D and E are mutually exclusive. D E Totals A 0.20 0.30 0.50 B 0.12 0.18 0.30 с 0.08 0.12 0.20 Totals 0.40 0.60 1.00 and P(E)P(D)= Are the events E and D independent? Select the correct answer below and fill in the answer boxes to complete your choice. and P(E)P(D)= O A. No, they are not independent because P(END)*P(E)P(D). P(End) = OB. Yes, they are independent because P(END) #P(E)P(D). P(END)= OC. Yes, they are independent because P(END)=P(E)P(D). P(END)= OD. No, they are not independent P(END) = P(E)P(D). P(END)= and P(E)P(D)= and P(E)P(D)=
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