Question 3 Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test.\( H_0: p = 0.6 \) versus \( H_1: p > 0.6 \)\( n = 200; x = 135; \alpha = 0.1 \)[Click here to view page 1 of the table.](#) [Click here to view page 2 of the table.](#)---Calculate the test statistic, \( z_0 \).\( z_0 = \) [Input box](Round to two decimal places as needed.) The image displays two standard normal distribution tables, one for negative \( z \)-values and another for positive \( z \)-values. These tables are essential for statistical analysis as they help determine the probability that a standard normal variable is less than or equal to a given value.**Standard Normal Distribution Table for Negative \( z \):**- **Rows and Columns:** The table is organized with \( z \)-values along the leftmost column, ranging from -3.4 to 0.0. The column headers represent the second decimal place of the \( z \)-value, from .00 to .09.- **Values:** Each cell contains the cumulative probability corresponding to that specific \( z \)-value. For instance, a \( z \)-value of -2.3 and a second decimal place of .04 would correspond to a probability of 0.0107.**Standard Normal Distribution Table for Positive \( z \):**- **Rows and Columns:** Similarly structured, the table shows \( z \)-values in the leftmost column, ranging from 0.0 to 2.8, and columns from .00 to .09.- **Values:** The probabilities in these cells indicate the cumulative probability for positive \( z \)-values. For example, a \( z \)-value of 1.5 with a second decimal place of .06 yields a probability of 0.9332.**Usage:**- These tables are used to find the probability of a standard normal variable being less than a specific \( z \)-value.- They aid in hypothesis testing, confidence interval calculation, and other statistical analysis involving standard normal distribution.Each table is color-coded for ease of reference, with alternating shades to differentiate rows and enhance readability.

GivenH0:p=0.6H1:p>0.6n=200x=135σ=0.1

Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test. Ho:p= 0.6 versus H,: p>0.6 n= 200; x = 135; a = 0.1 Click here to view page 1 of the table. Click here to view page 2 of the table. Calculate the test statistic, zo. Zo (Round to two decimal places as needed.)