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- C. Predicting Student Success STA believes there is a relationship between high school GPA (on a four-point scale) and college performance (as measured by GPA on a four-point scale). The following data were randomly selected from among students enrolling Fall 2020. HS GPA STA GPA Student 1 HS GPA STAGPA Student 21 2.9 2.5 3.6 3.4 2 3.4 3.1 3.0 22 3.4 4.0 1.7 3 3.1 23 2.9 2.9 1.7 3.0 3.2 3.3 4 24 3.5 5 3.4 25 4.0 3.6 3.6 3.0 26 3.6 3.8 3.2 3.9 3.1 27 8. 4.0 3.9 28 3.4 3.6 3.2 9. 3.0 3.0 29 3.7 10 2.9 2.0 3.0 30 4.0 3.3 4.0 3.2 11 3.3 31 12 3.6 3.8 32 3.7 3.2 3.4 3.0 13 3.7 3.9 33 14 3.8 3.6 34 2.5 2.0 15 2.5 2.5 35 2.9 2.9 3.7 2.2 16 2.9 2.5 36 3.8 17 2.8 2.1 37 2.9 18 3.8 1.7 3.5 38 3.6 3.5 3.6 19 3.7 39 3.6 20 3.9 3.0 40 3.1 3.6 Is high school GPA a good predictor of STA GPA? Why? What STA GPA would you predict for a student with a high school GPA of 3.75? How you would make the prediction.A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 37 46 59 83 225 No 213 204 191 167 775 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 475 randomly selected adults showed that 57% of them would erase all of their personal information online if they could. Find the value of the test statistic.
- A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station’s 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch11 p.m. News? 18 or less 19 to 35 36 to 54 55 or Older Total Yes 49 59 61 84 253 No 201 191 189 166 747 Total 250 250 250 250 1,000 (a) Let p1, p2, p3, and p4 be the proportions of all viewers in each age group who watch the station’s 11 p.m. news. If these proportions are equal, then whether a viewer watches the station’s 11 p.m. news is independent of the viewer’s age group. Therefore, we can test the null hypothesis H0 that p1, p2, p3, and p4 are equal by carrying out a chi-square test for independence. Perform this test by setting α = .05. (Round your answer to 3 decimal places.)…A plumber was interested in determining whether there is a significant difference in the price charged for plumbing tools by two hardware stores. The plumber selected five tools and recorded the price for each tool in each store. The following data was recorded: Store 1 2 Tool 2 R59.25 R22.50 R450 R44.25 R22.50 R36.75 R75 4 R480 R44.25 R60 Perform the appropriate test of hypothesis to determine whether there is a significant difference, on average, in the price of plumbing tools between the two stores, showing all 7 steps. Include both the rejection region and the p-value.A man was buying shoes wheb a salesperson commebted on hiw small his feet were. After telling her she had a lousy sales technique, he decided to inveatigate if he really does have feet that are smaller than the typical american man. If he is in the 20th percentile for shoe size among american men, is the saleswoman right or wrong?
- Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 488 randomly selected adults showed that 56% of them would erase all of their personal information online if they could. Find the value of the test statistic.Dataset: NES. Variables: spend8, nesw.) The NES dataset contains spend8, which records the number of government policy areas where respondents think spending should be increased. Scores range from 0 (the respondent does not want to increase spending on any of the policies) to 8 (the respondent wants to increase spending on all eight policies). The NES, of course, polls a random sample of U.S. adults. In this exercise you will analyze spend8 using the Analyze ▶ Compare Means ▶ One-Sample T Test procedure. You then will draw inferences about the population mean. Make sure you weight observations using the nesw variable so your results are nationally representative. A. The spend8 variable has a sample mean of ______.Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 455 randomly selected adults showed that 61% of them would erase all of their personal information online if they could. Find the value of the test statistic.
- A research study wanted to examine whether religious belief and gender are related in their state. They selected a representative sample of men and women in their State.Select the null and alternative hypothesis of the test: H0: there is no relationship between gender and belief about human originsHa: there is a relationship between gender and belief about human origins H0: there is a relationship between gender and belief about human originsHa: there is no relationship between gender and belief about human origins Results of the study are summarized in this table for the Belief about human origins: religious texts evolutionary theory total male 30 36 66 female 110 89 199 total 140 125 265 The degrees of freedom for the the ?2 statistic are Round the following numbers to two places after the decimal:The test statistic is ?2 = with a p-value = The conclusion of the test at the 5% significance level is There is not enough statistical evidence to suggest that gender…Political parties want to know what groups of people support them. The General Social Survey (GSS) asked its 2014 sample, "Generally speaking, do you usually think of yourself as a Republican, Democrat, Independent, or what?" The GSS is essentially an SRS of American adults. The large two‑way table provided breaks down the responses by the highest degree the subject held. None High School Jr. College Bachelor Graduate Strong Democrat 53 198 23 81 64 Not strong Democrat 52 204 31 70 49 Independent, near Democrat 40 163 26 66 42 Independent 118 251 36 67 30 Independent, near Republican 24 136 19 45 2525 Not strong Republican 19 142 30 71 30 Strong Republican 18 131 15 53 28 Other party 5 31 3 15 8 Use the four‑step process and the full table of counts to analyze the differences in political party support among levels of education. The sample is so large that the differences are bound to be highly significant, but provide the chi‑square statistic and its P‑value…The Global Business Travel Association reported the domestic airfare for business travel for the current year and the previous year. Below is a sample of 12 flights with their domestic airfares shown for both years. Do not round intermediate calculations. Current Year Previous Year Current Year Previous Year 468 231 285 216 342 282 699 498 552 360 675 255 252 192 702 222 396 375 477 381 234 174 621 357 What is the p-value? p-value (to 3 decimals) Degrees of freedom b. What is the sample mean domestic airfare for business travel for each year? Current Year $ (to 2 decimals) Previous Year $ (to 2 decimals) c. What is the percentage change in the airfare for the one-year period? % (to 2 decimals)
