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Test the equation for exactness and solve the equation using Method II: (2xy – 3x?)dx + (x² + y)dy = 0 a.x*y - x³ +y b. x?y – x2 +y? +ây = C = C c. x?y – x3 +y? = c 2- d. x?y – x³ +y =c e. none of these

Test the equation for exactness and solve the equation using Method II: (2xy – 3x?)dx + (x² + y)dy = 0 a.x*y - x³ +y b. x?y – x2 +y? +ây = C = C c. x?y – x3 +y? = c 2- d. x?y – x³ +y =c e. none of these

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Test the equation for exactness and solve the equation using Method II: (2xy – 3x?)dx + (x² + y)dy = 0 a.x'y x3 +y* = C b. x?y x2 +y? = c 2 1 c. x?y x3 +y2 = c 2- d. x?y x* +;y = C - e. none of these
Transcribed Image Text:Test the equation for exactness and solve the equation using Method II: (2xy – 3x?)dx + (x² + y)dy = 0 a.x'y x3 +y* = C b. x?y x2 +y? = c 2 1 c. x?y x3 +y2 = c 2- d. x?y x* +;y = C - e. none of these
Separation of Variables: y' = x-**) when x = 0; y = 0 a. y = ln e-x2+1 b. y = In e-x3+1 3 C. y = ln e-x3+1 2 d. y = In- %3D e-x2+1 e. none of these
Transcribed Image Text:Separation of Variables: y' = x-**) when x = 0; y = 0 a. y = ln e-x2+1 b. y = In e-x3+1 3 C. y = ln e-x3+1 2 d. y = In- %3D e-x2+1 e. none of these
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