Test the claim about the population mean, p, at the given level of significance using the given sample statistics.Claim: p=50; a =0.02; o = 3.06. Sample statistics: x 49.8, n 75Identify the null and alternative hypotheses. Choose the correct answer below.O A. Ho H<50O B. H, H=50H u> 50H2 p= 50O C. H, p> 50O D. Ho u 50Ha u= 50Ha = 50E. Ho =50Ha H#50O F. Ho H=50Ha: p< 50Calculate the standardized test statistic.The standardized test statistic is(Round to two decimal places as needed.)

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Answered: Test the claim about the population…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The null and alternative hypotheses are statements made about A. population parameters.B. sample parameters.C. sample statistics.D. either A or C.
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Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 7%; confidence level: 90%; from a prior study, p is estimated by 0.22. O A. 336 O B. 135 O C. 27 D. 95 Click to select your answer. tv MacBook Air
A business has just completed a marketing campaign. They want to determine if their original market share of 50% has increased as a result of the campaign. A survey conducted found 81 out of 150 people had bought the products. Determine whether the company has increased its market share i. Write down the null and alternative hypotheses for this test.ii. The sample proportion value is missing from the output above. What is this value?iii. Explain why we can use the following test static to conduct this test.? =?̂− ?√??⁄?iv. Use either the ?-value or the ? statistic in the output provided to conduct the test. Has the market share of the company increased?v. The marketing team plan to continue to monitor their market share. In a future study, they want to be able to estimate their market share to within +/−5% and with 90% confidence. What size sample is required? Use the sample proportion from part ii.
In the population of senior students at Shermer High School, the proportion who plan to attend college is 0.64. In a random sample of 100 students from this population, the proportion who plan to attend college is 0.75. We would call the value 0.64 a P-value. z-score. parameter statistic significance level.
What sample size is needed to give a margin of error within+3% in estimating a population proportion with 90% confidence? We estimate that the population proportion is about 0.25. Round your answer up to the nearest integer. Sample size = i
Use technology to help you test the claim about the population mean, p, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: u > 1280; a = 0.07; o = 196.31. Sample statistics: x= 1308.11, n= 200 H p> 1280 Ha: p 1308.11 O D. Ho: Hs 1308.11 Ha ps 1308.11 Ha: p> 1308.11 O E. H, p> 1280 O F. Ho: µ2 1280 Ha: u< 1280 Ha ps 1280 Calculate the standardized test statistic. The standardized test statistic is 2.03. (Round to two decimal places as needed.) Determine the P-value. P 3D (Round to three decimal places as needed.)
estimate the population proportion p,what is the minimum sample size we need in order to achieve a margin of error no more than 0.01 with a 95% cinfidence level? Similar study in the past suggest an guess of 0.1 for the value of p.
The US Department of Energy reported that 49% of homes were heated by natural gas. A random sample of 327 homes in Oregon found that 143 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 10% significance level. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0: H1: Based on the hypotheses, compute the following:b. Test Statistic = c. p-value = d. Based on the above we choose to e. The correct summary would be: that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 49%. Question HelpQuestion 14: Video1
Use technology to help you test the claim about the population mean, , at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: u> 1240; a = 0.09; o = 208.13. Sample statistics: x= 1267.96, n= 300 O E. Ho: us 1267.96 O F. Ho µ> 1267.96 Ha p> 1267.96 Ha µs 1267.96 Calculate the standardized test statistic. The standardized test statistic is (Round to two decimal places as needed.) Determine the P-value. P = (Round to three decimal places as needed.) Determine the outcome and conclusion of the test. V Ho. At the 9% significance level, there V enough evidence to the claim.
The US Department of Energy reported that 48% of homes were heated by natural gas. A random sample of 331 homes in Oregon found that 132 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 1% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0: H1: Based on the hypotheses, compute the following:Test Statistic = p-value = Based on the above we choose to The correct summary would be: that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 48%.
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.

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