Test the claim about the population mean, p, at the given level of significance using the given sample statistics.Claim: u = 50; a =0.02; o = 3.06. Sample statistics: x= 49.8, n= 75Identify the null and alternative hypotheses. Choose the correct answer below.O A. Ho H< 50О в. Но: и350Ha u= 50Ha p> 50О с. Но и> 50O D. Ho H 50H3 u= 50Ha: u= 50O E. Ho H= 50Ha p#50OF. H, H=50Hu< 50

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Answered: Test the claim about the population…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim about the population mean, µ, at the given level of significance using the given sample statistics. Claim: µ + 7000; a = 0.03; o = 410. Sample statistics: x = 6900, n = 35 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: µ+ 7000 Ha: u В. Но: и3D7000 Ha: u#7000 = 7000 С. Но: и#7000 Ha: us7000 D. Ho: µ#7000 Ha: µ2 7000 Ο Ε. H :μ> 7000 Ha: µ#7000 O F. Ho: µs7000 Ha:µ#7000 Calculate the standardized test statistic. The standardized test statistic is - 1.44. (Round to two decimal places as needed.) Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) O A. The critical values are ± B. The critical value is
Given a sample with r= 0.823, n= 10, and a= 0.05, determine the standardized test statistic t necessary to test the claim p= 0. Round answers to three decimal places. %3D О А. 3.816 В. 2.891 С. 4.098 D. 1.782
The population of all cans of Slurg Soda has an average of 12 ounces of soda per can. A manager randomly selects 45 cans of Sturg and finds an average of 12.1 ounces per can for this sample of cans. A distribution of 100 simulated sample statistics is shown below. 11.92 11.98 12 Sample means • What is the value of the sample statistic? Ор OI 12.04 Enter an integer or decimal number [more...] • Which symbol is used for the statistic in this situation? Ομ Оп A • Which of the following is an accurate statement? .O The average (mean) of the population of numbers is a 12.1. O The average (mean) of the population of numbers is = 12. O The average (mean) of the population of numbers is μ = 12. p O The average (mean) of the population of numbers is = 12.1. . Which of the following is the correct procedure to follow in order to identify the percentage of simulated statistics that are like theo m
What sample size is needed to estimate a population mean within 70 of the true mean value using a confidence level of 95%, if the true population variance is known to be 225,625? The sample size must be at least . (Round up to the nearest whole number.) Enter your answer in the answer box. lacBook
7. Bob draws a simple random sample from an original population. The sample size is n = 51, the sample 78, and the sample standard deviation turns out to be s = mean turns out to be x 14. Find the 95% confidence interval for the population mean µ. А. (74.062, 81.938) В. (74.062, 83.948) С. (74.062, 85.958) D. (74.062, 87.968)
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 3 percentage points and use a confidence level of 95%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n= (Round up to the nearest integer.) b. Assume that 25% of adults can wiggle their ears. n= (Round up to the nearest integer.) C
A marketing manager must decide on the size of the survey sample to be used in order to estimate the proportion of customers who are aware of her brand. She wishes to estimate this proportion to within 7 percentage points with 95% confidence. If the manager guesses that the proportion of aware customers is roughly 21%, what is the size of the sample that must be used? 131 ? CIlowerbound .2659 CIupperbound .314 Assume that 4700 customers were sampled, and that the sample proportion of aware customers was found to be 29%. Construct a 95% confidence interval for the population proportion of aware customers. X 0% ? × 0% ? X 0%
Determine the critical value(s). Select the correct choice below and fill in the answer box to complete your choice
In 2015, the average duration of long-distance telephone calls from a certain town was 3.9 minutes.A telephone company wants to perform a test to determine whether this average duration of longdistance calls has changed. Fifty calls, originating from the town, was randomly selected and thefollowing summary minutes.∑ ? = 205 ∑(? − ?̅)∑(? − ?̅)2 = 56.43 a) Calculate the sample mean, ?̅. b) Calculate the sample standard deviation c) Using the p value approach at the 1% level of significance, test whether the mean duration oflong-distance calls from the town had increased. d) Construct the 99% confidence interval for the population mean duration of the long-distance calls from the town. Answer sub-parts (d)
Find the minimum sample size needed to estimate the true mean with margin of error of 9 and at confidence of 90%. Assume the population range is 102. Select one: а. 49 O b. 54 С. 348 O d. 22 е. 21 O f. 19
7. Suppose a researcher wants to estimate the difference in proportions of firstborn between the college graduates and non-graduates to within 0.05, with 90% confidence. How many college graduates and non-graduates must he interview, assuming that an equal number will be interviewed from each group?
1.) Suppose that a teacher wants to see if a new teaching method improves test scores in their class. Luckily, they also know that the average score of all students in the United States in that grade is 85 and the sd is 10. Given that their class of 25 students’ (the sample) Mean score is 90... What is the standard error? 1 2 1.5 2.5 ----------------------------------------- 2.) Calculate the standardized effect size for question 1. What can you say about this effect size? It is a small effect size It is a moderate effect size It is a large effect size Cannot calculate the standardized effect size with the information given. ------------------------------------------------------------------------------------- 3.) Students have taken an exam. The mean was 70 and the standard deviation was 2. A student who scored 72, scored better than: 84% 30% 20% 99%…

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